regarding char array size

[zxc123]

#include <stdio.h>
main(){
int i=0;
struct emp
{
char t[6];
int x;
int y;
};
struct emp e = {"ram",304,678};
printf("%u\t%u\t%u\n",&e.t,&e.x,&e.y);
}

output:
2280780 2280788 2280792

--------------------------------

Is the (char t[6]) taking 8 bytes?

what is that extra two bytes b/w char array and (int x)

[weaknessforcats]

Those are pad bytes.

struct members usually align on an int boudary so the compiler had to add 2 bytes to align x on an int boundary.

[donbock]

Your format string doesn't match the types of any of the three values you're printing. That leads to undefined behavior -- which is a very bad thing. You should use %p instead of %u. Another way to inspect memory organization within a structure is to print the value of offsetof().