find out the largest and second largest number in an array

[sunithasiraj]

int a[10],i,l,s,n;
l=0,s=0;
printf("Enter the limit\n");
scanf("%d",&n);
printf("Enter the array\n");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
for(i=0;i<n;i++)
if(a[i]>l)
{
s=l;
l=a[i];
}
printf("\nLargest no.is%d",l);
printf("\nSecond Largest no.is%d",s);

[Banfa]

You haven't asked a question

[yasirassassin]

Hey dear here is a program to find second greater and third greater no i made two functions to get second and third greater no:


#include<iostream>
using namespace std;
int sec(int x,int y)
{
int greater;
if(x>y)
greater=x;
else
greater=y;
return greater;
}
int third(int x,int y,int z)
{ int m;
m=sec(sec(x,y),z);
return m;

}

int main()

{
int a,b,c,z,d;
cin>>a;
cin>>b;
cin>>z;

c=sec(a,b);
cout<<"2nd greater : "<<c<<endl;

d=third(a,b,z);
cout<<"finally Third greater no is: "<<d<<endl;

system("pause");
return 0;
}
Hope it helps:))

[praveensundarpv]

@sunithasiraj: Program u posted will not work out for the following inputs :
1) limit = 5, values are 50, 40, 30, 20, 10. the output is 50, 50.
2) This will not find out the largest for Negative numbers too...( Limit = 5, values are -50 -40 -30 -20 -10 and the output is 0, 0)

[Maraj]

Here is the program which Outputs First and second largest number

// max.cpp : Defines the entry point for the console application.
//Finds second maximum number in the array.
 
#include "stdafx.h"
#include<iostream>
using namespace std;
void max(int [],int *,int *);            //Define a function max which gives maximun ans second maxium number.
                        //Pass two int variables by-refernce and an array.
 
int _tmain(int argc, _TCHAR* argv[])
{
    int max1,max2,i,a[5];            //Define three int variables and an array of your required size.
    cout<<"enter array elements"<<endl;    //Input value of array elements.
    for(i=0;i<5;i++)            //Loop for input.
    {
    cin>>a[i];
    }
    max(a,&max1,&max2);            //Call the function.
 
 
 
    cout<<"\nMaximum number is"<<max1<<endl;//These lines will execute after function execution.
    cout<<"\n 2nd maximum number is"<<max2<<endl;
    return 0;
}
 void max(int b[5],int *m1,int *m2)        //Function will receive address of variables and array.
 {    int j,min=b[0];                //Define an int min required to find second maximum number.
    *m1=b[0];
 
    for(j=0;j<5;j++)            //First find maximum number.            
    {
    if(b[j]>*m1)
    *m1=b[j];                //Maimum number is in *m1.
    }
    for(j=0;j<5;j++)            //Now find minimum nubmer.
    {
        if(b[j]<min)
            min=b[j];        //Minimum nuber goes to min.
    }
    *m2=min;
    cout<<"\nMinimum number is"<<min<<endl;
 
    for(j=0;j<5;j++)            //Now here the logic for second maximum number.
    {
 
                        //If b[J] is greatar than *m2 and b[j] is less than *m1 which is maximum number
                        //then assign *m2 the value of element of array pointing currently.
    if(b[j]>*m2 && b[j]<*m1)        
    {
    *m2=b[j];
 
    }
    }
 
 
 }
 
 

[whodgson]

why not just sort the array....the largest will be the last array element and the second largest will be the second last element.
if the array is a[200]then sort it with sort(a,a+200) which is defined in the <algorithm> header. a[199]and a[198] will be the largest and second largest resp.

edit:providing last element NOT duplicated