characters and word count

[margel dorado]

int main()

{

int countch=0;
int countwd=1;
cout << "Enter your sentence in lowercase: " << endl;
char ch='a';
while(ch!='\r')
{
ch=getche();
if(ch==' ')
countwd++;
else
countch++;
}
cout << "\n Words = " << countwd << endl;
cout << "Characters = " << countch-1 <<endl;
getch ();
return 0;
}

my question is when u enter "good boy" why is that the cout of words are 2 and the characters is 7?

[johny10151981]

did you debug through your code??

look at the condition..

if(ch==' ')
countwd++;
else
countch++;
 

when ch==' ' is true the it only increase the countwd but not the countch. at the end when you press enter button it increase your countch once again. in the output you have showed countch-1. that is why you are getting 7

But if you input "I am a good boy"
The character count will be 11 but you have 16 character including '\r'

There is more: if user input "good boy ", the character count will be 7 and word count will be 3, the reason is, you are counting space inorder to count words.funny thing is the more space you add the more word count you will get

[whodgson]

In other words you are saying don't count space characters as characters.