copy array from one function to another

[Malibu Code]

Dear all, I wish to copy the aray aRSG from the first function to the next. Please help, Urgent. I have attached my code

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
 
// RANDON SEQUENCE GENERATOR FUNCTION
char RSG(int x)
{
     char RandomRSG[5] = {'a','b','c','d'}; //array for sequence to be generated
     int iRSG;     // variable for counting for loop
    char vRSG; // character variable
    char aRSG[50];    //array to store random sequence
    int countRSG = 0;// counter
    int i;
    srand(1);
    printf("RANDOM SEQUENCE GENERATOR WILL NOW GENERATE A,B,C OR D RANDOMLY\n\n");
 
    for (iRSG=0; iRSG<20; iRSG++)
        {
        if((rand()%7) == 0){
              vRSG = RandomRSG[3];
              }
              else if((rand()%9) == 0){
              vRSG = RandomRSG[2];
              }
              else if((rand()%3) == 0){
              vRSG = RandomRSG[1];
              }
              else if(rand()%rand()!=0){
              vRSG = RandomRSG[0];
            }
            aRSG[countRSG] = vRSG;
            countRSG++;
 
 
 
 
    }
    for (i=0; i < 20; i++)
        printf("%c\n", aRSG[i]);
    return aRSG[x];
}
 
InputSelector() {
    int y =0;
    RSG(y);
    int i=0, z=0, a=0, b=0, c=0, d=0, x=0;
    char Mac1Array [20], Mac2Array [20], Mac3Array [20], Mac4Array [20];
    char j,q=0;
    char Selector[50] = aRSG[50];
 
 
    for(i = 0; i<20; i= i+1) {
        q = Selector[z];
 
 
 
       switch(q) {
               case 'A' :
 
                    Mac1Array [a] = Selector[z];
                                          a++;
                          break;
            case 'B' :
                    Mac2Array [b] = Selector[z];
                                        b++;
              break;
            case 'C' :
                    Mac3Array [c] = Selector[z];
                                        c++;
              break;
            case 'D' :
                                        d++;
                    Mac4Array [d] = Selector[z];
 
              break;
            default:
            break;
 
       }
        z++;
    }
    printf("THE VALUES IN MACHING ONE IN ORDER OF ARIVAL ARE:\n");
    for (i=0; i < 20; i++)
        printf("%c\t", Mac1Array[i]);
    printf("THE VALUES IN MACHING TWO IN ORDER OF ARIVAL ARE:\n");
    for (i=0; i < 20; i++)
        printf("%c\t", Mac2Array[i]);
    printf("THE VALUES IN MACHING THREE IN ORDER OF ARIVAL ARE:\n");
    for (i=0; i < 20; i++)
        printf("%c\t", Mac3Array[i]);
    printf("THE VALUES IN MACHING FOUR IN ORDER OF ARIVAL ARE:\n");
    for (i=0; i < 20; i++)
        printf("%c\t", Mac4Array[i]);
 
    return 0;
}
 
 
 
int main(void)
{
    InputSelector();
    return 0;
}

[weaknessforcats]

aRSG is a local variable. As such, it will be destroyed whn you leave te first function. To preserve it, allocate te array on heap using malloc(). Then have the function either a) return the array address or b) have a second argument tha is the address of a pointer of the array type. The first function can then place the address of the array in th pointer address passed in.

You will also need a companion variable that contains the number of elements. This companion is passed around as needed. In C, when you only know the array address, the array appears as a pointer to element 0 and the number of elements is lost. This is called decay of array and is something you need to be aware of.