Convert a HexaDecimal char array to a Char Array Or String in C

[Lohith r]

Hi Friends,
I have a serious and irritating problem, please help

mdContext->digest[i] is an unsigned char Array with hexadecimal values so


for (i = 0; i < 16; i++)
printf ("%02x", mdContext->digest[i]);

prints 900150983cd24fb0d6963f7d28e17f72

now.... I want to get this value in a char Array, i.e if I do

printf("%s",ArrayConverted);
I want to print the above string... Please help me in doing this




Things I tried

Trial-1
unsigned char in[64]=0;
int tempValue[64];


for (i = 0; i < 16; i++){
sprintf(&tempValue[i],"%02x", (unsigned char)mdContext->digest[i]);
in[i]=(unsigned char)tempValue[i];
}

printf("%s\n\n\n",in);


This prints
90593d4bd9372e77 But Original content is 900150983cd24fb0d6963f7d28e17f72


So it is skipping many characters in between... please help me converting this hexadecimal Char array in to a String

[Lohith r]

I found the answer myself.... Finally, I did this.

char buf[33];
int j=0;
for ( i=0; i<16; i++) {
sprintf(&buf[j], "%02x",mdContext->digest[i]);
j=j+2;
}
buf[32]=0;


I suspected if the next char that is being lost is stored in the next byte... and it is true... It worked, But can any one help me understand this behavior? Thankyou

[Lohith r]

i.e Int is also 2Bytes... when it didnot work in the firstcase, why in the second? why does it take 2 Chars and not 1 int size