Can i have a single template object based on the type given by user?

[Rupal Shah]

Like the functionality i want to achieve is as under: but it will not work. How can i achieve the same functionality?

 
# include <iostream.h>
# include <conio.h>
 
template <class T>
class Test
{
    T a;
    public:
        void set()
        {
            cin>>a;
        }
        void display()
        {
            cout<<"A is"<<a<<endl;
        }
};
 
int main()
{
    int choice;
    cin>>choice;
    if(choice == 1)
    {
        Test<int> obj;
    }
    else if(choice ==2)
    {
        Test<char> obj;
 
    }
    else
    {
        Test<float> obj;
 
    }
    obj.set();
    obj.display();
    return 0;
}
 

[hype261]

I haven't tested this out, but I believe you can solve this problem using an interface class.

using namespace std;
 
class Interface
{
public:
virtual void set() = 0;
virtual void display() = 0;
};
 
template<typename T>
class Test : public Interface
{
public:
virtual void set()
{
cin >> a;
}
 
virtual void display()
{
cout << a;
}
private:
T a;
};
 
int main()
{
Interface * obj;
 
int choice;
cin >> choice;
 
if(choice == 1) 
    { 
        obj = new Test<int>(); 
    } 
    else if(choice ==2) 
    { 
        obj = new Test<char>(); 
 
    } 
    else 
    { 
        obj = new Test<float>; 
 
    } 
    obj.set(); 
    obj.display(); 
    delete obj;
    return 0;
}