in the printf the program remove all the strings after the space why???

[ehab mohamed]

#include<stdio.h>
void num(char arr[100])
{
int i=0, count=1;
while (arr[i]!='\0')
{
if (arr[i]==' ')
{count++;}
i++;
}
printf("%d",count);
}
int main()
{
 
char data [100];
 
scanf("%s",&data);
printf("%s",data);
num(data);
return 0;
}

try to inter programming language
in the printf in the main it will printf programming only and remove the rest

[Banfa]

No that is not printf getting it wrong, that is scanf behaving exactly as specified.

scanf uses any white space as a delimiter so if you ask scanf for a string and enter "programming language" it will use the space as a delimiter and return "programming" which printf then correctly outputs.

If you want to get a whole line including spaces using the end of line as a delimiter then use the function fgets.

[ehab mohamed]

how can u give me an example

[Banfa]

Perhaps you could try typing "fgets" into your browser search engine?

[ehab mohamed]

okai thanks

[donbock]

Better than typing 'fgets' into the browser ...

1. Look for "bytes > c/c++ > c/c++ questions" in small print near the top of this browser page (just above the thread title).
2. Click on "c/c++ questions".
3. Then click on the first question: "PLEASE READ FIRST: Useful Links and Posting Guidelines"
4. Scroll down to the second message in this thread. It contains Important Links.
5. Click on either of the "C and C++ library reference" links.
6. Now search for fgets.

[ehab mohamed]

when i replace the space between the words by tab it didn't work in a right way
any help in this !!

[Banfa]

There is no reason why it would work any differently, tab is also a white space character.

[donbock]

Refer to reply #2. Use fgets. Don't use scanf.

[mysticwater]

Options to get rid of current problem:
gets() function instead of scanf [although this is often frowned upon]
fgets() function instead of scanf

or continue using scanf but clear the buffer with a while loop.
Google: clean buffer after scanf for more details on this.