How to get a structure variable in function?

[Sajini Biju]

Can I get a structure variable in function
for eg:-

struct stud{ 
            char name[20]}stud1;
 
void student(char);
void main()
{
    char n[20];
    scanf("%s",n);
    strcpy(stud1.name,n);
    student(stud1.name);
}
void student(char k)
{
   printf(k);
}

[Banfa]

Do you mean can you pass it to a function? Yes.

The question you need to ask is what is the type of stud1.name. That is nothing to do with structures but rather is a question about arrays.

Once you can answer that question then you just need to give your function parameter that type.

As a clue you already pass stud1.name to another function at line 9. What type does that function use to accept it?

[Oralloy]

Sajini Biju,

You have several couple choices, depending on what you need to accomplish.

You can pass just the address of the name array:

void student(char *);
void main()
{ 
    char n[20]; 
    scanf("%s",n); 
    strcpy(stud1.name,n); 
    student(stud1.name); 
} 
void student(char *k) 
{ 
   printf("%s", k); 
}

You can pass the entire stud structure:

...
void student(struct stud);
void main()
{ 
    char n[20]; 
    scanf("%s",n); 
    strcpy(stud1.name,n); 
    student(stud1); 
} 
void student(struct stud k) 
{ 
   printf("%s", k.name);
}

You can pass a reference to the stud structure:

...
void student(struct *stud);
void main()
{ 
    char n[20]; 
    scanf("%s",n); 
    strcpy(stud1.name,n); 
    student(&stud1); 
} 
void student(struct stud *k) 
{ 
   printf("%s", k->name);
}

Note, too, that I inserted a format in your printf() call. This is to guard against the case where the string to be printed has something that appears as a format specification, which would then result in garbage out.

Luck!