Malformed if statements and program flow help

[edithgingras]

the idea here is to eliminate all solutions except for the square. I am stuck in trying to figure out how to utilize the if statement in the choice. I know its probably simple but its driving me crazy. any sugestins on how to make this better would be appreciated be specific do i need to remove something or add thank you

#include <iostream>
#include <string>
 
using namespace std;
 
const int SQUARE = 1;
const int TRIANGLE = 2;
const int RECTANGLE = 3;
const int CIRCLE = 4;
 
int main()
{
 
    // Declare Variable
 
    int multiply;
    int number5;
    int number6;
 
    // Declare Choice
 
    int choice;
 
 
    // Display Choice
 
        cout << " What is the area of a square, triangle, rectangle, or circle? " ;
        cout << " Make your choice? /n " ;        
        cout << SQUARE << " ) Square: /n " ;
        cout << TRIANGLE << " ) Triangle: /n " ;
        cout << RECTANGLE << " ) Rectangle: /n " ;
        cout << CIRCLE << " ) Circle: /n "  ;
 
 
 
    // Get users choice
 
        cin  >> choice ;
 
    // Display Proper feedback based on users choice          
 
 
        if (choice == TRIANGLE ) RECTANGLE ; CIRCLE; {
              cout << " Choose another: /n" ;
 
        }
 
            if ( choice == SQUARE ) ;{
           cout << "The area of a square is: /n" ;
           }
 
    // Get one side
                cout << " Enter one side: /n ";
                cin >> number5;
 
    // Get the other side
                cout << " Enter other side: /n";
                cin >> number6;
 
    // Multiply one side by the other
                multiply = number5 * number6 ;
 
    // Display sum
 
            cout <<  "Mulitply is " << multiply << endl;
 
 
system ("pause");
 
    return 0;
 
 
}

[Banfa]

if (choice == TRIANGLE ) RECTANGLE ; CIRCLE; {

is mal formed, you need to check choice individually against each value you are interested in using the logical operators (&& ||) etc for example

int a;
 
cin >> a;
 
if (a == 4 || a == 8)
{
    cout << "a is either 4 or 8) << endl;
}
 

On line 48 you have a ; which will stop the if statement doing what you want.

I think lines 52 - 65 should be inside the code block for the if ( choice == SQUARE ) condition.

[edithgingras]

ok I dont get how to do exactly what you mean when i try to set it up that way it has run errors so I am still missing something here

[whodgson]

if(choice=TRIANGLE||choice=RECTANGLE||... )choice=SQUARE;
Maybe enum shape = {SQUARE,TRIANGLE......};//might be neater

[edithgingras]

anymore suggestions here really could use some help

[Banfa]

Err no other than writing you if statement the correct way you are unlikely to get further suggestions.

Perhaps you should post the corrected code and the run time errors you are getting.