how to take integers out of a scrambled text?

[trea]

so I have this c++ homework which wants me to take a text input like "north6east7west8"(the string follows the "direction+integer order) and have an input check. if the text does not have any integers it ought to give a warning message.

and in another function I should take the integers out of the text (which I have no idea how to do) and convert them with atoi (which I could do).

I hope I explained it clearly. Thanks in advance.

[tetrahedral]

@trea
So what exactly is your question?

Also, please see the FAQ about asking for homework solutions.

[weaknessforcats]

Consider using the >> operator.

cin >> data;

and data is a char, you have fetched one character. If data is not a char, then the >> operator fails.

So you might try:

cin >> anInt;
 
If this fails then the data is not an integer, try again using a char
 
cin >> aChar;

Wrap this in a loop an off you go.


Note that an input of 1234x and you perform cin>>anInt will place the value 1234 in anInt. That is, you do not use atoi or atoanythingelse in C++.

[whodgson]

Another way maybe to get the length of the string 's' with s.length()run through your string within a for loop,using < s.length() as the end condition, and identify the integers with something like if(s[i] >= '0' && s[i]<='9') and increment count++ so that you can print out the number of integers. Can you guarantee there will be only one character in each integer? If not you will need to check if s[i-1] is or is not also an integer.
Alternatively if s[i] is >='a' && <='z' you could could replace 'a' --> 'z' with " " which would leave only the integers.