Copying a row of a two dimensional array into a one dimensional array

[v859]

I am trying to string copy using strcpy, a row of a two dimensional array into a one dimensional array.

Can I do this?

    void function(char tempArray[][10])
{
    int i;
     int j;
     string minimum;
 
 
     for(i=0; i< MAX_SIZE; i++)
    {
         location = i;
         strcpy(minimum,tempArray[i]);
     }
 
}
 
 

How about this?

 
    void function(char tempArray[][10])
{
    int i;
     int j;
     char minimum[];
 
 
     for(i=0; i< MAX_SIZE; i++)
    {
         location = i;
         strcpy(minimum[],tempArray[i]);
     }
 
}
 

[v859]

I didn't mean for that to be in a for loop.

I meant to say

 
char tempArray[10][10];
string minimum;
 
int i = 4;
int location = i;
strcpy(minimum, tempArray[i]);
 

or

 
char tempArray[10][10];
char minimum[]
 
int i=4;
strcpy(minimum,tempArray[i]);
 

[whodgson]

What happens when you compile and run the code?

[v859]

I did get a can not convert char to char error message, but that is when I had

 
char temporary;
char array[10][10];
 
strcpy(temporary, array[10]);
 
 

Which is now obvious why I got that error, trying to put a string into a single char variable.

I don't know what happens when I try it the ways I listed above, since I do not have a C++ compiler on this computer.

[weaknessforcats]

strcpy() starts copying from the address of the second argument and doesnt't stop until it hits a binary zero.

Therefore, using strcpy() in this fashion will never guarantee that 10 bytre are copied.

Is using strcpy() a homework requirement? If not, I sugget using strncpy() and tell it to copy only 10 bytes.

Since all arrays are one dimensional, you need only locate the starting address and copy 10 elements from there.

[v859]

I was able to solve those problems. Thanks for the help. I have a new problem though that I will post about in a new thread.