can't able to get output

[rampraveen]

#include"main.h"
int i;
int sum=0;
void main()
{
char choice;
printf("enter E-->even O-->odd");
choice=getch();
choice=toupper(choice);
if(choice=='E')
{
void even();
getch();
}
else if (choice=='O')
{
void odd();
getch();
}
else
{
printf("choice is wrong");
}}
void even()
{
for (i=0;i<100;i+=2)
{
sum+=i;
}
printf( "\n%4d %4d",i-2,sum);
}
void odd()
{
for(i=1;i<100;i+=2)
{
sum+=i;
}
printf("\n%4d %4d",i-2,sum);
}

IF any body knows pls tell....if i run i can 't able to get any output..but it does not give any error....

[newb16]

because you call it like
void even();
, it is not called.

[rampraveen]

so how can i call that function..? what changes i have to do in that program? pls tell..

[newb16]

The same way as you call printf.

[jkmyoung]

Get rid of the word void before the function name, when you are calling it.

[rampraveen]

really thanks.....i got correct output...

[donbock]

The following syntax is used for function prototypes:

void even();
int odd();

Function prototypes are good, but they do not usually occur within a block. A function prototype declares the function (that is, it tells the compiler that this function exists). Nothing wrong with declaring the function, but what you truly want to do at those points in your program is call the function.

What has your teacher or textbook said about how to use functions?