please help me to check the code..

[ballpen1019]

my problem occur when run the program is i cant enter the value that i want to in the function(float read(float x[10],y[10]).

#include <stdlib.h>
#include <stdio.h>
#include <math.h>
 
 
 main ()
 {
  float read(float x[10],float y[10]);
  float calculate_A(float x0,float y0);
 
 
 
      float a,b;
      float x[10];
      float y[10];
      float x0,x1,x2,y0,y1,y2;
      a=x0,b=y0;
 
      printf("the mean value for x is %f",a);
      printf("the mean value for y id %f",b);
 
 
      getch();
      }
 
      loat read(float x[10],float y[10])
      { int n,i;
       float x0,y0;       
       float x[10],y[10];
 
 
      puts("enter the number of data(n):\n");
      scanf(" %d",&n);
      puts("enter the values for x:\n");
      for(i=0;i<=9;i++)
      {scanf(" %f",&x[10]);}
      puts("enter the values for y:\n");
      for(i=0;i<=9;i++)
      {scanf(" %f",&y[10]);}
      return ;
       //system("pause");
      }
      float calculate_A(float x0,float y0)
      {
            int n,sum1,sum2,sum;
 
            float x[10],y[10];
            sum1=sum+x[10];
            x0=sum1/n;
            sum2=sum+y[10];
            y0=sum2/n;
            printf("%f",x0);
            printf("%f",y0);
            return(x0,y0);
            }
 
      //system("pause");

[weaknessforcats]

It looks like a confusion on the two arrays and and y. You have them defined in every function. I would expect you define them once in main and then call your functions using the addresses of the arrays:

float x[10];
float y[10];
 
 
MyFunc(x, y, 10, 10);

where:

void MyFunc(float* a, float* b, int numelements_x, numelements_y)
{
     Here a[1] is the same as x[1] in main.
}

You need to pass in the number of elements since the name of an array is the address of element 0 and from inside the function all you can see is this address. The number of elements in the array hhas been lost. This is called

decay of arra

y and is just a thing to live with.

Be sure to call your functions after the arrays are defined in main().

[ballpen1019]

thank u weaknessforcats..i have one question to ask u...how i suppose to send a value from a function to a function???i cannot send the values that i enter from the first function to another function...can you help me to check the code...thank you...

#include<stdlib.h>
#include<stdio.h>
#include<math.h>
float read(void);
void calculate(float*sum1,float*sum2);
main ()
 
{     float a,b,sum1,sum2;
    read();
 
     printf("%f",&sum1);
     printf("%f",&sum2);
     system("pause");
  }
     float read(void)
     {
           int n,i;
           float x[10],y[10];
           puts("please enter a value of n:\n");
           scanf("%d",&n);
           puts("please enter the values for x:\n");
           for(i=0;i<n;i++)
           {scanf("%f",&x[i]);}
 
           puts("please enter the values for y:\n");
           for(i=0;i<n;i++)
           {scanf("%f",&y[i]);}
           return((x[i],y[i]));
           }
           void calculate(float *sum1,float*sum2)
           {
 
                int n,i;
                float x[i],y[i];
                float sum=0;
                read();
                *sum1=(sum+x[i]/n);
                *sum2=(sum+y[i]/n);
                }

[weaknessforcats]

Please remember that a function when has completed executing, that is, when it returns, is an instance of its return type. That is,

int MyFunc();

MyFunc() becomes an int if you execute it. SO this code:

int y = MyFunc();

is prefectly OK becuase the compiler knows that by calling MyFunc() it will get the correct int value to assign to y. So this code:

void AnotherFunc(int arg);
 
AnotherFunc(MyFunc());

is also OK. The compiler knows that by calling MyFunc() it eill get the int value to supply to the arg argument of AnotherFunc.

This is NOT OK:

void Func();
 
int y = Func();

void means "no type". Here the compiler knows that by calling Func() that nothing will be returned so there will be nothing to initialize y. In this case ytou get a compile-time error.