divide first column from a txt file

[balambur]

hy guys,
I am a beginner in c and from 3 days I have a big question...
I have a file containing the folowing data:
5971 -44 976 -23
5981 -53 980 -23
5991 -50 978 -21
6001 -56 975 -21
6011 -58 971 -21
6021 -52 981 -24
6031 -49 974 -22
6041 -50 981 -31
6051 -47 978 -37
6061 -42 978 -38
6071 -37 977 -42
I need to divide the first column by 600 to convert in to seconds and write it out into a new file first column divided and the second, 3'th, 4'th leave it like is it now....
can anyone help me?
please???
Thanx a lot

[whodgson]

I know this sounds like buck passing but why don`t you rewrite the file with an extra field populated by col_1/600........then refer to this field direct

[jkmyoung]

Also, how did you want the column formatted? Did you want only whole seconds, or decimals to the tenth?

[balambur]

#include <stdio.h>
#include <conio.h>
void main(void)
{
FILE *pointer_fisier;
FILE *pointer_fisier2;
int t,x,y,z,c;

pointer_fisier2=fopen("datepout.txt","w");
if ((pointer_fisier = fopen("peter6.txt", "r")) == NULL)
printf("Error opening peter6.txt for input\n");
do{
fscanf(pointer_fisier, "%d %d %d %d", &t, &x, &y, &z);
c=t/600;
fprintf(pointer_fisier2, "\n t = %4d \t x = %4d \t y = %4d \t z = %4d",c,x,y,z);
}while(!feof(pointer_fisier));
fclose(pointer_fisier);
fclose(pointer_fisier2);
printf("\n End!!!");getch();
}



this is it... I must take a book and remember some c but it is working now...