Passing pointer as parmaneter

[randysimes]

I have to pass a pointer as a parameter, but I can't quite get the syntax down.

I have this variable:
std::vector<Foo> fooVector;

And this function of another class, Foo
void Add (Foo * N)

So I need to pass fooVector_[size_t] to the Add function.

I have tried this:
Foo foo;
foo.Add(foo.fooVector_[size_t]) but get the error (shortened) Needs class::Foo* not class::Foo&

Could you please point* me in the right direction.

[weaknessforcats]

fooVector is implemented as an array of foo. Therefore, fooVector[size_t] is a foo. Therefore, &fooVector[size_t] is a foo*.

[randysimes]

Thanks so much, weaknessforcats!

[randysimes]

So, say that the void Add(Foo * N) function has access to a private variable that is a list and I want to add more than one item at any given item in the list. For instance, I want to add a North, and South to item 0 in the list, how can I do this?

[Banfa]

Call the function twice, unless you are able to write a function with more semantic meaning such as

void Foo::AddExits(Foo* northExit, Foo* southExit, Foo* eastExit, Foo* WestExit);

[randysimes]

Banfa, thanks, but I was going in the wrong direction with that.
However, say I have

class Foo
{
  Bar * start;
  start = &fooVector[size_t]
...
}
class Bar
{
...
}

How can I output the value of start? I did not overload the operator << so I cannot cout << *start

[weaknessforcats]

You would need to call methods on class Bar that return the values you are interested in.