function that accepts 2 parameters an unsigened char and a pointer to character

[mostafaAlderea]

the function converts the first parameter into a string containing the hexadecimal equivalent of the number

[mostafaAlderea]

iam a student and i am beginner in programming but i can not understand how to change a char into a string

[mostafaAlderea]

and also how the string containing the hexadecimal equivalent of the number

what i know is that strings is an arrau of character

[whodgson]

//A string is a series of characters.
string s="This is my hex number - 0xff";
cout<<s; //prints--> This is my hex number - 0xff
cout<<dec<<0xff; // prints 255
/*Or you can use a container like an array 
so that each array element from 0 up contains 
each character from the first onwards.*/
char a[]={'0','x',1,2,3,4,'/0'};  //initialize a 7 element 
                           //array with a hex number
for(int i=0;i<6;i++) //traverse array and print its individual
// elements 
cout<<a[i];//prints 0x1234
cout<<dec<<0x1234;   // prints 4660
//hope this helps.

[whodgson]

I see.....you wish to write a function which converts an integer (in hexadecimal format) into a string?.....yes?
If so consider the following.
int hex_num=0;
cout<<"enter an integer in hex format";
cin>>hex_num; //say 0x1234 is entered

string convert_hex_to_string(hex_num) //conversion function of type string
{
string s=hex_num; //now s contains the string " 0x1234"
return s;
}
cout<<s;//prints 0x1234
Is that what you are trying to do.....or is it something else entirely?