int main error

[macaireb]

I am very new with C++
I have an assignment that follows

Write a C++ program containing a for loop to print the message
DooBeeDooBeeDooBeeDooBeeDooBeeDooBee Do

My code so far is

#include <iostream>
using namespace std;

int main ()
{
int Doo;
int Bee;

for (int Doo = 0; Doo < 6; Doo++)
for (int Bee = 0; Bee < 6; Bee++)
std::cout << "Bee"<<std::;
std::cout << "Doo"<<std::;
}




My error messages follows

DooBee.cpp: In function âint main()â:
DooBee.cpp:11: error: expected unqualified-id before â;â token
DooBee.cpp:12: error: expected unqualified-id before â;â token

[weaknessforcats]

std::cout << "Bee"<<std::;

Did you mean:

std::cout << "Bee"<<std::endl;

?

Also, the int Bee in main() is a different variable from the int Bee that's inside the for loop.

[macaireb]

I didn't mean endl I need it all on one line.

What do you suggest to fix the main ()

[weaknessforcats]

Take the word int out of your for loops.

What this is doing is creating another int named Bee that is local to the loop. This local variable is hiding the one you defined outside the loop. Do this for both variables.

[macaireb]

Done still got these three messages


DooBee.cpp: In function âint main()â:
DooBee.cpp:11: error: expected unqualified-id before â;â token
DooBee.cpp:12: error: expected unqualified-id before â;â token

[macaireb]

New Code is

#include <iostream>
using namespace std;

int main()
{
int Doo;
int Bee;

for (Doo = 0; Doo < 6; Doo++)
for (Bee = 0; Bee < 6; Bee++)
std::cout << "Bee"<<std::;
std::cout << "Doo"<<std::;
}

[drhowarddrfine]

Shouldn't it be this? (It should compile but I know it won't do what he wants.)

#include <iostream>
using namespace std;
 
int
main()
{
int Doo;
int Bee;
 
for (Doo = 0; Doo < 6; Doo++)
for (Bee = 0; Bee < 6; Bee++)
cout << "Bee";
cout << "Doo";
}
 

[myusernotyours]

A loop without braces is only done for the next one line of code. If you want it done for two or more lines you have to enclose your loop in braces;

for(int i = 0 ; i < 10 ; i++)
std::cout << i;
std::cout << i;
 

is different from

for(int i = 0 ; i < 10 ; i++){
std::cout << i;
std::cout << i;
}
 

Regards,

Alex.

[macaireb]

I am sorry for the newbish question but after i compile it how do I run it

[Banfa]

That rather begs the question how are you compiling it?

From the command line? From a IDE? If its from an IDE which IDE (for example Visual C++, Eclipse, Dev-C++, CodeBlocks)?

On what operating system?

[macaireb]

Command Line inside WinSCP
Windows 64bit vista

[Banfa]

Which compiler are you using?

Anyway regardless of that the result of a compilation, assuming no errors, should be an object file, extension .obj on a Windows machine. You would then link the object with libraries and other objects to produce a executable file, extension .exe.

However most modern compiler interfaces are actually interfaces onto the entire tool chain. This means you can initiate a compile followed by a link from a single command.

If you have a .exe in the directory you are compiling in then that is what has happened. If you only have a .obj then you have compiled but not linked. In the latter case try telling the compiler you would like an executable output, normally with the -o <outputfilename> switch. Give your output file name a .exe extension (this works with gcc/g++ I am not so sure about the Microsoft compiler).

[macaireb]

Oh im sorry im not trying to run it independent. I just want to check it in the command line to make sure its working.

[whodgson]

Do you mean the last Do has to have a space in front of it?
If not something like this may serve..

string s1="DooBee";
string s2="Do";
    for(int i=0;i<6;++i)
    if(i==5)cout<<s2;
    else cout<<s1;

otherwise the second last line should read:

if(i==5)cout<<" "<<s2;

[macaireb]

Excellent responses and suggest, I will be on these forums for a long time to come

[macaireb]

Last Question for this topic I promise lol.

The program compiles and runs smooth but it prints out at the very beginning of my command line.

Is there a way to put in a endline to fix this