For loops

[MrPickle]

When I define a for loop like so:

for(initialize; condition; increment)
{
   //code
}

Is the condition only called once?

For example:

for(unsigned int i = 0; i < foo(); i++)
{
   //code
}

Would foo() be called several times, or only once?

Sidenote: I know I could easily test this but it's bugging me and I do not currently have a compiler.

[Tassos Souris]

Well if you know the theory behind for loops you know that the condition statement determines whether the body of the loop is to be executed again or not... If the expression evaluates to true then the body of the for loop is executed; otherwise the for loop terminates.

[samimmu]

it will be called only once but if u want to call tat function more than one then you need to specify

for (int i=0; i<8; i++)
{
foo();
}

it will be called 8 times

[donbock]

@samimmu
Totally untrue.

If you go through a for-loop N times, then the second clause of the for-instruction will execute N+1. If that clause includes a function call then the function is called that many times. The only exception is if the second clause is a logical expression and short-circuiting prevents the evaluation of all terms in that expression.

[samimmu]

actually i tried but it is not working very well, anyways, i have a question?

[samimmu]

@donbock
i have a question can i ask you ?

[maiyappan]

untill the value return from the foo() will be greater than i
the function will be called when condition check occur.