C - How do you assign more than one char to a single case (switch function)

[JasonD]

I figure this is a pretty basic question so I'll just show an excerpt from my small source file for an example, rather than uploading it.

I have WinXP32 Pro and DevC/C++.

Note that everything is declared, just not included. I want to know how to include upper and lowercase letters into the same function rather than repeat the whole case over and occupy more space. I tried to use || (or), it compiles but it assigned the uppercase Y to the default case instead.

"...
if(setoff=1) switch(yes_no)
{
case 'y' || 'Y' : printf("\nCare to make it interesting?\n\n Place bet in Canadian Dollars, no change: $");
scanf("%d", &bet); printf("\n1)Rock, 2)Paper, 3)Scissors\n"); scanf("%d", &rps);
..."

Thanks for any help.

[JosAH]

You can use more than one case label:

switch (chr) {
   case 'y':
   case 'Y': // yes
                break;
   case 'n':
   case 'N': // no
                break;
}
 

kind regards,

Jos

[donbock]

By the way, "if(setoff=1)" is wrong. That assigns "1" to setoff and unconditionally takes the true path through the if-else statement.

There are two basic strategies:

1. Test for both uppercase and lowercase letters.
2. Convert the input to lowercase (or uppercase) and test only for letters of that case.

There are many ways to implement these strategies.

[kkrish]

Hi,

Instead of returning char values, it will be good to return int values like 0,1 etc;