find even or odd in array

[AsHantoosH]

#include<stdio.h>

main() {

int a;

printf("Enter a: \n");

scanf("%d", &a);


if (a % 2 == 0) {

printf("The given number is EVEN");

} else {

printf("The given number is ODD");

}

}

the above program find the even or odd but how can i find multiple of 2 for array of 100 elemens

[scruggsy]

@AsHantoosH
Any even number is a multiple of 2. No odd number is. So it looks like you already have most of the code to do this, you just need to do it inside a loop inspecting the elements of your array one at a time. If that's the part you're having trouble with, post what you've tried.

As a somewhat useless aside, another way to test if an integer is odd or even:

if (a & 1)  // odd
else   // even

[donbock]

@AsHantoosH
By "multiple of 2", do you mean "even" (2, 4, 6, 8, 10, ...) or do you mean "power of two" (2, 4, 8, 16, 32, ...)?

[AsHantoosH]

i mean multiple of 2 (2,4,6)

[Meetee]

In your even number logic you can extends the logic for the multiplicity of 2 as every even number except 0. So modify your logic accordingly.

Regards

[scruggsy]

@zodilla58
Not to be nitpicky (or rather, to be very nitpicky :p) but zero is a multiple of all numbers but a factor of none. Negative even numbers are also multiples of 2. Whether either applies in this case depends on the problem statement I guess - OP doesn't specify.

[rahulthapar07]

[ incorrect spoonfeeding code deleted ]

Jos (moderator)