Contracting a Square matrix

[momotaro]

Am trying to come up with an algorithm that Creates the following output if the input is 8 (8x8):

1 1 1 1 1 1 1 1
1 2 2 2 2 2 2 1
1 2 3 3 3 3 2 1
1 2 3 4 4 3 2 1
1 2 3 4 4 3 2 1
1 2 3 3 3 3 2 1
1 2 2 2 2 2 2 1
1 1 1 1 1 1 1 1

I know the "merror" methode but am looking for a more efficient algorithm

thx for your help!

[JosAH]

Suppose both x and y run from -4 to 4. The displayed number equals
5-max(|x|, |y|).

kind regards,

Jos

[momotaro]

Sorry but I didn't get your point ?

[JosAH]

@momotaro
I answered your question: if both x and y run through the values [-4, 4] the function value I described equals the values you wanted.

kind regards,

Jos

[momotaro]

So if I hade it right it is:

Displayed_number = [(input_number%2) + 1] - Max(|-input_number %2|,|input_number % 2| )
Because the input number might change (1..10)

thanks in advance

[momotaro]

Because for even input it will overflow by one:

if input is 8 we will have 9x9 matrix