char to TCHAR

[97612]

Below are my codes,and I want to use TCHAR to replace the char

/****************************************
const char* ptr = NULL;
char newPath[100];

ptr = strrchr(absPath, '.');
strncpy(newPath, absPath, ptr - absPath + 1);
newPath[ptr - absPath + 1] = '\0';

*******************************************/

Below are modified codes with some logic errors, anyone can tell me what's wrong?

/*******************************************
const TCHAR* ptr = NULL;
TCHAR newPath[100];

ptr = _tcsrchr(absPath, _T('.'));
_tcsncpy(newPath, absPath, ptr - absPath + 1);
newPath[ptr - absPath + 1] = (const TCHAR) _T('\0');

********************************************/
Thanks for your answers!

[donbock]

It would help immensely if you told us what errors are being reported by the compiler or what run-time misbehavior you're seeing.

Did you include the TCHAR header? (I think it is called tchar.h)

[97612]

Dear donbock,

Thanks for your reply, my problem is solved , thanks!

Below are the working code:

const TCHAR* ptr = NULL;
TCHAR newPath[100];

ptr = _tcsrchr(absPath, _T('.'));
_tcsncpy(newPath, absPath, ptr - absPath + 1 );
newPath[ptr - absPath + 1] = TCHAR('\0');