Lvalue Required...getting this error message

ramesh nambiar reloaded

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 #include<stdio.h>

 #include<string.h>

 #include<conio.h>

 #include<dos.h>

// #include<object.h>
 
 const char *hex = "0123456789ABCDEF";
 
 char *bin2hex(char *string);

 int binstring2number(char *string);

 char *number2hexstring(int nr);
 
 char *hex2bin(char *string);

 int hexstring2number(char *string);

 char *number2binstring(int nr);
 
 void main(void)

 {
 
   int x,y,z,i;

   char temp_string[80];

   clrscr();
 
   //while(!kbhit())

   //     {

     x=inport(0x37A);

     y=x|0x20;

     outportb(0x37A,y);

     z=inportb(0x378);

    // printf("%x",z);

    temp_string[80]=z;
 
     //delay(200);

     printf("\n");

     //     }
 
    printf("The value in the port is");

    printf("%sb\n", hex2bin(temp_string));
 
    //while(!kbhit());

    getch();

 }
 
 char *bin2hex(char *string)

 {

    int nr = 0;

    char *hexstring;
 
    nr = binstring2number(string);
 
    hexstring = number2hexstring(nr);
 
    return hexstring;

 }
 
 int binstring2number(char *string)

 {

    int temp_nr = 0, i;

    int len;
 
    len = strlen(string);
 
    for(i = 0;i != len;i++)

        temp_nr |= (string[i] - '0') << (len - i - 1);
 
    return temp_nr;

 }
 
 char *number2hexstring(int nr)

 {

//    char *temp = new char[10];

    char *temp[10];

    //temp=char[10];
 
    int i;
 
    for(i = 0;i < 4;i++)

        temp[i] = hex[(nr >> ((3 - i) * 4)) & 15];
 
    temp[i] = '\0';
 
    return temp;

 }
 
 char *hex2bin(char *string)

 {

    int nr = 0;

    char *binstring;
 
    nr = hexstring2number(string);
 
    binstring = number2binstring(nr);
 
    return binstring;

 }
 
 int hexstring2number(char *string)

 {

    int temp_nr = 0, i, j;

    int len;
 
    if((len = strlen(string)) > 4)

        len = 4;
 
    for(i = 0;i < len;i++)

    {

        for(j = 0;j != 16;j++)

            if(string[i] == hex[j])

                temp_nr |= (j << ((len - i - 1) * 4));

    }
 
    return temp_nr;

 }
 
 char *number2binstring(int nr)

 {

       //char *temp = new char[20];

    char *temp[10];

    int i;

    for(i = 0;i != 16;i++)

        temp[15-i] = ((nr >> i) & 1) + 48;
 
    temp[i] = '\0';
 
    for(i = 0;i != 15;i++)

        if(temp[i] == '1')

            break;
 
    temp +=i;
 
    return temp;

 }

while debugging i got error like Lvalue Required....
plse suggest a solution..

~added code tags
-stang02gt

Stang02GT

What language is this?

Please make sure you are using code tags when you are posting your code. And I think you are going to need to provide more information if we are going to try and help you.

You need to read our Posting Guidellines

RedSon

Its C or C++ something like that.

JosAH

[quote=ramesh nambiar reloaded]

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   char temp_string[80];

   ...

    temp_string[80]=z;

*boing* that's an OBOE (Off By One Error)

kind regards,

Jos

newb16

while debugging i got error like Lvalue Required....

When *compiling*. When you press debug, it compiles and links first and then debug.

plse suggest a solution..

Identify location ( by line number mentioned in error message). Identify left part of the assignment. Fin wy it can't be there.

Expand|Select|Wrap|Line Numbers

 
 char *temp[10];

    int i;

    for(i = 0;i != 16;i++)

        temp[15-i] =

'Off by 6' error.
... And you should not return pointers to local variable in this way.

Lvalue Required...getting this error message

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