Accessing a typedef type that was defined within a template class

[Alex Snast]

Hello guys,

I can't seem to be able to get accsess to a type i declared within a
template class i.e.

template <typename T>
class Array {
public:
typedef std::size_t size_type;

....
....
size_type size() const;

....
private:
....
};

Now i want to implement the size method outside on the class so:
template <typename T>
size_type Array<T>::size() const { ... }

now i know that i can't just use "size_type" but using something like
Array<T>::size_type or Array::size_type can't seem to work either,
however writing T works just fine.

My question is how can i use my typedef size_type outside of the class
declaration?

Any help would be much appreciated, Alex

[acehreli]

On Aug 30, 12:37*pm, Alex Snast <[e-mail]:

template <typename T>
class Array {
public:
* * *typedef std::size_t * * * *size_type;

...
...
* * size_type size() const;

[...]

Now i want to implement the size method outside on the class so:
template <typename T>
size_type Array<T>::size() const * * *{ ... }

'typename' before the return type:

template <typename T>
typename Array<T>::size_type Array<T>::size() const
{
return 0;
}

Ali

[Alex Snast]

On Aug 30, 10:32*pm, [e-mail] wrote:

On Aug 30, 12:37*pm, Alex Snast <[e-mail]:

template <typename T>
class Array {
public:
* * *typedef std::size_t * * * *size_type;

...
...
* * size_type size() const;

[...]

Now i want to implement the size method outside on the class so:
template <typename T>
size_type Array<T>::size() const * * *{ ... }

'typename' before the return type:

template <typename T>
typename Array<T>::size_type Array<T>::size() const
{
* * return 0;

}

Ali

Thanks Ali, works now.