[snip]
>{
for (i = 0; i < in2; i++)
{
if (i == 0)
//printf("- %d\n", &view_var1[i]);}
printf("- %d\n",var1[i]);
>{
else
//printf("%d %d\n", i-1, &view_var1[i]);}
printf("%d %d\n", i-1, var1[i]);
}The return type is int* but here you return int. The correct
return 0;
}
int* function(int in1, int in2)
{
int i = 0;
if (var1 != NULL)
free(var1);
var1 = (int*)malloc (sizeof(int*)* in2);
for (i = 0; i < in2; i++)
{
if (i == 0)
var1 [i] = 0;
else
{
if (i == 1)
var1[i]= 1;
else
var1[i] = var1[i-1]*2+in1;
}
}
return (var1[in2]);
}
way would be to write:
return var1+in2;
But then again, that just returns a pointer pointing beyond the
allocated array. I'm guessing you actually want the beginning
of the array:
return var1;
--
OU
