Template parameters

[saneman]

I have something like this:

template<typename math, typename real, typename vector, typename matrix>
void fun(real a, vector v, matrix m)
{
typedef typename math::line line;
.....
}
but real, vector and matrix are all types included in math. Is there some
technique to only supply math as a template parameter eventhough real,
vector and matrix are used as function arguments in fun?

[Leandro Melo]

On 19 ago, 11:09, "saneman" <[e-mail]:

I have something like this:

template<typename math, typename real, typename vector, typename matrix>
void fun(real a, vector v, matrix m)
{
* * * * typedef typename math::line line;
* * * * .....

}

but real, vector and matrix are all types included in math. Is there some
technique to only supply math as a template parameter eventhough real,
vector and matrix are used as function arguments in fun?

Hi.

Yes, the same way you did inside the function body:

template<typename math>
void fun(typename math::real a, typename math::vector v,
typename::matrix m)
{
typedef typename math::line line;
.....

}

Probably, you also might wanna consider passing those parameter by
const-ref (or just by ref if you're to modify them). For example:
const typename math::real&.

--
Leandro T. C. Melo

[Gernot Frisch]

but real, vector and matrix are all types included in math.

are they?
I guess std::vector, std::real and std::matrix might be. But vector, real
and matrix are not.
It's the price for using "using namespace std;", I guess.

[Leandro Melo]

On 19 ago, 12:19, "Gernot Frisch" <[e-mail]:

but real, vector and matrix are all types included in math.

are they?
I guess std::vector, std::real and std::matrix might be. But vector, real
and matrix are not.
It's the price for using "using namespace std;", I guess.

I think that in this case those types are user-defined ones from the
OP. Naturally, naming a user-defined class as 'vector' might not be a
good idea.

--
Leandro T. C. Melo