Recently seen question answer: Returning pointer to function syntax

[Ampodayas]

I've seen alot of confusing explanations for how to return a function pointer without a typedef, so here it is in plain english:

(Return of func pointer being returned) ((class name)::(function to call name)(function to call args)(func pointer to return args){
}

(Note: the class anme ins't needed if it isn't in a class, it's just there for completeness.)

the "function to call name" is not the name of the pointer, but the name of the function that is returning the pointer

[gpraghuram]

I am not very clear with the question...
Are you asking how to return a funtion pointer from a function without typedef?

Following is a sample code to returna function pointer

typedef int (*FUN)(int);
int abc(int x)
{
    return 0;
}
FUN fun_ret_funptr(void)
{
    return abc;
}
 

Raghu

[weaknessforcats]

You cannot return a function pointer from a function.

Functions have a return type. That means you have to return a type or a pointer to a type.

Therefore, you have to typedef your function pointer so it becomes a type. Then you can return it as a pointer to a type.