Using system to pass arguments

[kardon33]

I need to pass a variable from C witch is a 209 bit char to a php script.

I was thinking that I would use the system function than add the char to the end after the file name.

Any thoughts how to do that.


I know that doesn't work but thats the idea.

    char buf[209];
    system("php /var/www/htdocs/test.php &buf");
 
 

[Banfa]

That will not work, what you will get passed to the PHP script is the string "&buf".

There is no automatic way to add your data to the php command line, you are going to have to construct a string containing it using functions like sprintf before calling system.

[kardon33]

Ok so i tried doing what you said but no luck yet,

I have successfully put my two char together into one complete one. However when i go and use the system call on php only the string part of the argument is passed.

The argument I am trying to pass is a byte with the first 7 characters letters and that works till that point and the rest are hex but they don't get passed.

Any Ideas?

 
    int i=0, h=0;
    char  all[238] = "php /var/www/htdocs/test.php ";
 
      while(i < 237)
      {
 
        if(i > 28){ all[i] = buf[h];  h++;  }
                printf("%d-    %c    -    %x         %d \n", i,  all[i],  all[i],  all[i] );
 
        i++;
      }
 
    system(all);
 
 

[Banfa]

The argument I am trying to pass is a byte with the first 7 characters letters and that works till that point and the rest are hex but they don't get passed.

They wouldn't, you can only pass text on the command line, you with have to encode your binary data in a text format (may be it's hexidecimal representation) and then the PHP script will have to decode it back into binary.

[Banfa]

Also you never terminate the string all with a NULL terminator, tobe passed to system it has to be a zero terminated string.