A MACRO question

[ManicQin]

Hi all.

Is there a way to iterate through a pre-defined list in pre-compile
time?
(not with for)

something like:

#define LIST int,double,float,string......
#define MAX 10
#define functionPattern(type) \
void return##type() { \
cout << #type << endl; \
}

//Replacing the next macro
#define functionCreator \
functionPattern(LIST[1]) \
functionPattern(LIST[2]) \
..
..
..
functionPattern(LIST[MAX])

Thanks

[puzzlecracker]

On Jul 22, 7:46*am, ManicQin <[e-mail]:

Hi all.

Is there a way to iterate through a pre-defined list in pre-compile
time?
(not with for)

something like:

#define LIST int,double,float,string......
#define MAX 10
#define functionPattern(type) \
void return##type() { \
cout << #type << endl; \

}

//Replacing the next macro
#define functionCreator *\
functionPattern(LIST[1]) \
functionPattern(LIST[2]) \
.
.
.
functionPattern(LIST[MAX])

Thanks

Please explain what this means:

void return##type() { \
cout << #type << endl; \
}

Is it even legal C++ code?

[Pete Becker]

On 2008-07-22 08:57:16 -0400, puzzlecracker <ir*********@gmail.comsaid:

On Jul 22, 7:46Â*am, ManicQin <[e-mail]:

>Hi all.

Is there a way to iterate through a pre-defined list in pre-compile
time?
(not with for)

something like:

#define LIST int,double,float,string......
#define MAX 10
#define functionPattern(type) \
void return##type() { \
cout << #type << endl; \

}

//Replacing the next macro
#define functionCreator Â*\
functionPattern(LIST[1]) \
functionPattern(LIST[2]) \
.
.
.
functionPattern(LIST[MAX])

Thanks

Please explain what this means:

void return##type() { \
cout << #type << endl; \
}

Is it even legal C++ code?

No, but that's not the full text of the macro. The full text is:
#define functionPattern(type) \
void return##type(){\
cout << #type << endl;\
}

and, yes, it's legal. return##type concatenates "return" and the
replacement text for "type" into a single token. And #type is simply
the replacement text for "type" surrounded by quotes. So, for example:

functionPattern(foo)

would expand to

void returnfoo(){
cout << "foo" << endl;
}

Try it.

--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)

[ManicQin]

On Jul 22, 1:54*pm, "Alf P. Steinbach" <[e-mail]:

Yes, the Boost library provides some sophisticated (really unbelievable) macro
magic.

Thanks I looked at how Boost do it and because I cant use Boost
I could only steal their code... but it's too much work more work
than I can afford to spent on just saving few lines...
Thanks!