warning: statement has no effect

[dissectcode]

Hello - I am trying to eliminate warnings in my code...and have a question...

I have a function

void function_name(void)
{
  functionA();
}
 

which goes to a file that says:

 
#define functionA()   functionB()
 

which finally goes to:

#define functionB() (0)
 

I need to keep these macro definitions there, but it obviously doesn't do anything right now. What can I put in this code to supress that warning??

Thanks!

[Banfa]

Well you could put in a ; instead of (0) but then you couldn't use functionA in an expression. It partly depends on what the nominal return type of functionA is supposed to be.

[dissectcode]

Thanks for the response... I tried putting a ; instead of (0) but the warning did not go away. What can I do?

Thanks!

[oler1s]

In Visual C++, for example, I would have followed the advice at http://msdn.microsoft.com/en-us/library/2c8f766e.aspx. (Specifically, I would have used the push/pop mechanism indicated at the bottom of the page.)

It depends on the compiler to try and disable the warning.

[JosAH]

Most (if not all) compilers keep their mouth shut if a value is cast to a void; as in:

(void)functionA();
 

kind regards,

Jos