bitset in C

[rudra]

i have a C++ program

#include <bitset>
#include <iostream>

int main()
{
int i = 23356;
int j=~i;
printf("One's complement of i=%u is ~i=%u\n",i,~i);
std::cout << std::bitset<32>(i);
printf("\n");
std::cout << std::bitset<32>(j);
}

is there any equivalent way of bitset in C? or easier way of doing the
same thing in C?

[Victor Bazarov]

rudra wrote:

i have a C++ program

#include <bitset>
#include <iostream>

int main()
{
int i = 23356;
int j=~i;
printf("One's complement of i=%u is ~i=%u\n",i,~i);
std::cout << std::bitset<32>(i);
printf("\n");
std::cout << std::bitset<32>(j);
}

is there any equivalent way of bitset in C? or easier way of doing the
same thing in C?

If you need help with C, shouldn't you be asking in the comp.lang.c
newsgroup? Just checking...

V
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Please remove capital 'A's when replying by e-mail
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[Juha Nieminen]

rudra wrote:

is there any equivalent way of bitset in C?

As a general rule, the C library doesn't offer *any* utility functions
or data containers, except those related to I/O and some string
manipulation.
(The only exception is qsort(), which in itself is slower than
std::sort().)

[vova777]

On Jul 9, 9:29*am, rudra <[e-mail]:

is there any equivalent way of bitset in C?

The int is good enough for most of the C developers.

or easier way of doing the same thing in C?

Printing the bits of integer? The C developers tend to prefer hex
format. Anyway, printing bits does not take much.

#include <stdio.h>

void print_bits(int n)
{
unsigned bits = 8 * sizeof n;

while(bits--)
putchar('0' + (n >bits & 1));
}

int main()
{
int i = 23356;
int j=~i;
printf("One's complement of i=%u is ~i=%u\n",i,~i);
print_bits(i);
printf("\n");
print_bits(j);
}

Regards,
Vladimir

[Victor Bazarov]

vo*****@gmail.com wrote:

On Jul 9, 9:29 am, rudra <[e-mail]:

>is there any equivalent way of bitset in C?

The int is good enough for most of the C developers.

>or easier way of doing the same thing in C?

Printing the bits of integer? The C developers tend to prefer hex
format. Anyway, printing bits does not take much.

#include <stdio.h>

void print_bits(int n)
{
unsigned bits = 8 * sizeof n;

<nitpick>

Shouldn't this be

unsigned bits = CHAR_BIT * sizeof n;

? (CHAR_BIT comes from <limits.h>)

</nitpick>

>
while(bits--)
putchar('0' + (n >bits & 1));
}

int main()
{
int i = 23356;
int j=~i;
printf("One's complement of i=%u is ~i=%u\n",i,~i);
print_bits(i);
printf("\n");
print_bits(j);
}

Regards,
Vladimir

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

[vova777]

On Jul 9, 6:08*pm, Victor Bazarov <[e-mail]:

* * *? (CHAR_BIT comes from <limits.h>)

Good point, thanks!

Regards,
Vladimir

[Lionel B]

On Wed, 09 Jul 2008 10:02:25 -0700, vova777 wrote:

On Jul 9, 9:29Â*am, rudra <[e-mail]:

>is there any equivalent way of bitset in C?

Not in general... see below.

The int is good enough for most of the C developers.

A std::bitset can be an arbitrary (compile-time constant) number of bits.
Maybe not a concern for the OP if they only want 32 bits and/or all they
need to do is print them out. Full std::bitset functionality will be much
more hassle to achieve in C - basically you rewrite the internals of
std::bitset, except that you're not allowed to use templates ;-)

--
Lionel B