pointer

[vim]

hi guys

this is my code
#include<stdio.h>
main()
{
char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;
}
I want to print the string "helwornicsho" by using ptr increment or
decrement.
How can I do that.
I tried to print charachter by charachter .
But for that increment ptr pointing to each charachter .
I used (**p1)++.But it is giving segmentation fault.
Plz tell the error.

[vim]

Please another thing is there is statement after
char **p1;
p1=p;

[Vladimir Oka]

vim wrote:

hi guys

this is my code
#include<stdio.h>
main()
{
char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;
}
I want to print the string "helwornicsho" by using ptr increment or
decrement.
How can I do that.
I tried to print charachter by charachter .
But for that increment ptr pointing to each charachter .
I used (**p1)++.But it is giving segmentation fault.
Plz tell the error.

If you can't explain what exactly you want to achieve, and if you won't
post the code you tried and failed, there's little chance anyone can
help.

I guess you want to print first three characters of each element of
`p`, possibly with the first one of each being forced to lowercase. In
which case, this should do you nicely:

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
char *p[]={"hello" ,"world" ,"Nice","show"};
int i,j;

for (i = 0; i < (sizeof p / sizeof p[0]); ++i)
{
/* no error checking here */
for (j = 0; j < 3; ++j)
{
printf("%c", tolower(p[i][j]));
}
}
printf("\n");

return 0;
}

Be warned, I did not include checks to see whether any of the array
elements are long enough (i.e. have at least three characters).

[Vladimir Oka]

vim wrote:

Please another thing is there is statement after
char **p1;
p1=p;

Quote context, even when replying to own posts. Read
<http://cfaj.freeshell.org/google/>.

I have a sneaky suspicion you've been told this before (and more than
once). If you want to be taken seriously here, please follow the advice
in the link above, and also below:

<http://www.clc-wiki.net/wiki/Introduction_to_comp.lang.c>

[Vladimir Oka]

Vladimir Oka wrote:

vim wrote:

hi guys

this is my code
#include<stdio.h>
main()
{
char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;
}
I want to print the string "helwornicsho" by using ptr increment or
decrement.
How can I do that.
I tried to print charachter by charachter .
But for that increment ptr pointing to each charachter .
I used (**p1)++.But it is giving segmentation fault.
Plz tell the error.
If you can't explain what exactly you want to achieve, and if you won't
post the code you tried and failed, there's little chance anyone can
help.

I guess you want to print first three characters of each element of
`p`, possibly with the first one of each being forced to lowercase. In
which case, this should do you nicely:

#include <stdio.h>
#include <stdlib.h>

Sorry, it should have been:

#include <stdio.h>
#include <ctype.h>
int main(void)
{
char *p[]={"hello" ,"world" ,"Nice","show"};
int i,j;

for (i = 0; i < (sizeof p / sizeof p[0]); ++i)
{
/* no error checking here */
for (j = 0; j < 3; ++j)
{
printf("%c", tolower(p[i][j]));
}
}
printf("\n");

return 0;
}

Be warned, I did not include checks to see whether any of the array
elements are long enough (i.e. have at least three characters).

[pete]

Vladimir Oka wrote:

vim wrote:

hi guys

this is my code
#include<stdio.h>
main()
{
char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;
}
I want to print the string
"helwornicsho" by using ptr increment or decrement.
How can I do that.

I guess you want to print first three characters of each element of
`p`, possibly with the first one of each being forced to lowercase. In
which case, this should do you nicely:

#include <stdio.h>
#include <stdlib.h>
I think you mean "ctype" instead of "stdlib"

int main(void)
{
char *p[]={"hello" ,"world" ,"Nice","show"};
int i,j;

for (i = 0; i < (sizeof p / sizeof p[0]); ++i)
{
/* no error checking here */
for (j = 0; j < 3; ++j)
{
printf("%c", tolower(p[i][j]));
}
}
printf("\n");

return 0;
}

Be warned, I did not include checks to see whether any of the array
elements are long enough (i.e. have at least three characters).

It could be a little more pointer incremental.

/* BEGIN new.c */

#include <stdio.h>
#include <ctype.h>

#define THREE 3

int main(void)
{
char *p[] = {"hello" ,"world" ,"Nice","show"};
char **p1;
int x;

for (p1 = p; *p1 != p[sizeof p / sizeof *p]; ++p1) {
for (x = 0; x != THREE; ++x) {
putchar(tolower(*(*p1)++));
}
}
putchar('\n');
return 0;
}

/* END new.c */
--
pete

[Andrew Poelstra]

On 2006-05-18, vim <vg*****@gmail.com> wrote:

hi guys
You are already annoying me with your lack of capitals.
this is my code One sec, here's a cleaned up version:

#include <stdio.h>
int main(void)
{
char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;

p1 = p; /* As per your most recent post */
/* You should have posted context */

/* Actual code here */
return 0;
}
I want to print the string "helwornicsho" by using ptr increment or
decrement. What is "ptr"? I don't see it in your code.
How can I do that.
I tried to print charachter by charachter . Easier to set the fourth character of each string to '\0' and then
printf ("%s", p[i]), no?
But for that increment ptr pointing to each charachter .
I used (**p1)++.But it is giving segmentation fault.
**p1 points to the letter h, which is part of a string literal. You
don't need to increment that, and if you could you'd end up with 'i'
instead of the next letter.

Use *p1++ to jump to the next word, and p1++ to jump to the next
letter. The parentheses are unnecessary.
Plz tell the error.

What does "plz" mean? That isn't in your code either.

--

Andrew Poelstra < http://www.wpsoftware.net/blog >

[pete]

pete wrote:

Vladimir Oka wrote:

vim wrote:

hi guys

I forgot to mention,
anyone who does your homework for you, isn't being your friend.
/* BEGIN new.c */
/* END new.c */

But if you ask questions, they will be answered.

--
pete

[Fred Kleinschmidt]

"vim" <vg*****@gmail.com> wrote in message
news:11**********************@j33g2000cwa.googlegr oups.com...

Please another thing is there is statement after
char **p1;
p1=p;

Where is the context? I see two statements here; where is the rest?
What is your question?
--
Fred L. Kleinschmidt
Boeing Associate Technical Fellow
Technical Architect, Software Reuse Project

[Vladimir Oka]

pete wrote:

Vladimir Oka wrote:

vim wrote:

hi guys

this is my code
#include<stdio.h>
main()

<snip>
I guess you want to print first three characters of each element of
`p`, possibly with the first one of each being forced to lowercase. In
which case, this should do you nicely:

#include <stdio.h>
#include <stdlib.h>

I think you mean "ctype" instead of "stdlib"

Yes. Thanks. (I did notice myself, as well, albeit too late).

<snip>

Be warned, I did not include checks to see whether any of the array
elements are long enough (i.e. have at least three characters).

It could be a little more pointer incremental.

It was deliberate. I wasn't going to do OP's homework. ;-)

[Thad Smith]

Andrew Poelstra wrote:

On 2006-05-18, vim <vg*****@gmail.com> wrote:

One sec, here's a cleaned up version:

#include <stdio.h>
int main(void)
{
char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;

p1 = p; /* As per your most recent post */
/* You should have posted context */

/* Actual code here */
return 0;
}

I want to print the string "helwornicsho" by using ptr increment or
decrement.
...
How can I do that.
I tried to print charachter by charachter .

Easier to set the fourth character of each string to '\0' and then
printf ("%s", p[i]), no?

Easier, possibly, but resulting in undefined behavior if the strings are
string literals as defined above.

--
Thad

[Dave Thompson]

On Thu, 18 May 2006 14:42:27 GMT, Andrew Poelstra
<ap*******@localhost.localdomain> wrote:

char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;

p1 = p; /* As per your most recent post */
/* You should have posted context */ <snip> Use *p1++ to jump to the next word, and p1++ to jump to the next
letter. The parentheses are unnecessary.

p1++ or ++p1 to jump to the next word and
(*p1)++ (parens necessary) or ++*p1 for next letter.

- David.Thompson1 at worldnet.att.net

[Andrew Poelstra]

On 2006-05-29, Dave Thompson <da*************@worldnet.att.net> wrote:

On Thu, 18 May 2006 14:42:27 GMT, Andrew Poelstra
<ap*******@localhost.localdomain> wrote:

char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;

p1 = p; /* As per your most recent post */
/* You should have posted context */

<snip>

Use *p1++ to jump to the next word, and p1++ to jump to the next
letter. The parentheses are unnecessary.

p1++ or ++p1 to jump to the next word and
(*p1)++ (parens necessary) or ++*p1 for next letter.

- David.Thompson1 at worldnet.att.net

I tested my method in gcc. I think that you are correct
about the parentheses (for style reasons, at the very least),
but when I compiled the OP's code (which may have been
different from the example code quoted), p1++ moved to the
next letter, not word.

--
Andrew Poelstra < http://www.wpsoftware.net/blog >
To email me, use "apoelstra" at the above address.
It's just like stealing teeth from a baby.

[Joe Wright]

Andrew Poelstra wrote:

On 2006-05-29, Dave Thompson <da*************@worldnet.att.net> wrote:

On Thu, 18 May 2006 14:42:27 GMT, Andrew Poelstra
<ap*******@localhost.localdomain> wrote:

char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;

p1 = p; /* As per your most recent post */
/* You should have posted context */

<snip>

Use *p1++ to jump to the next word, and p1++ to jump to the next
letter. The parentheses are unnecessary.

p1++ or ++p1 to jump to the next word and
(*p1)++ (parens necessary) or ++*p1 for next letter.

- David.Thompson1 at worldnet.att.net

I tested my method in gcc. I think that you are correct
about the parentheses (for style reasons, at the very least),
but when I compiled the OP's code (which may have been
different from the example code quoted), p1++ moved to the
next letter, not word.

It's not for style. Remember p1 is a pointer which points to a pointer.
p1++ will advance p1 to the next pointer.

puts(*p1++); /* prints hello */
puts(*p1--); /* prints world */
puts(++(*p1)); /* prints ello */

--
Joe Wright
"Everything should be made as simple as possible, but not simpler."
--- Albert Einstein ---

[Andrew Poelstra]

On 2006-05-29, Joe Wright <jo********@comcast.net> wrote:

Andrew Poelstra wrote:

On 2006-05-29, Dave Thompson <da*************@worldnet.att.net> wrote:

On Thu, 18 May 2006 14:42:27 GMT, Andrew Poelstra
<ap*******@localhost.localdomain> wrote:

char *p[]={"hello" ,"world" ,"Nice","show"};
char **p1;

p1 = p; /* As per your most recent post */
/* You should have posted context */
<snip>
Use *p1++ to jump to the next word, and p1++ to jump to the next
letter. The parentheses are unnecessary.

p1++ or ++p1 to jump to the next word and
(*p1)++ (parens necessary) or ++*p1 for next letter.

- David.Thompson1 at worldnet.att.net

I tested my method in gcc. I think that you are correct
about the parentheses (for style reasons, at the very least),
but when I compiled the OP's code (which may have been
different from the example code quoted), p1++ moved to the
next letter, not word.

It's not for style. Remember p1 is a pointer which points to a pointer.
p1++ will advance p1 to the next pointer.

puts(*p1++); /* prints hello */
puts(*p1--); /* prints world */
puts(++(*p1)); /* prints ello */

That is true for the example code quoted, but the OP's code behaved
differently. Oh well. I wasn't sure why it worked at the time, and
it has long since been deleted, so I can't check my work.

Anyway, I wasn't aware that parentheses were needed, so I learned
something very important today. (That bug has burned me several times,
and yet I never remember it). Thanks.

--
Andrew Poelstra < http://www.wpsoftware.net/blog >
To email me, use "apoelstra" at the above address.
It's just like stealing teeth from a baby.