program won't work

[Bingo Bongo]

My aim is to show that the armonic series diverges, by showing that it's bigger of any given real number b
If you consider b=2 as argument of NSA the while cycle should do four iterations and then return s=4. Well...
it doesn't. What's the problem?
#include<stdio.h>

int NSA(float b){

int i=1;
int s=0;

float sum=0;

while(1){
sum+=(1/i);
s=s+1;
if(sum>=b)
break;
else
i=i+1;
}
return s;
}

int main() {
float a;
int m;
printf("Choose a real number: ");
scanf("%f",&a);
m=NSA(a);
printf("The minimum n for which the armonic series is equal to %f is %d\n ",a,m);
}

[pete]

Bingo Bongo wrote:

My aim is to show that the armonic series diverges, by showing that it's bigger of any given real number b
If you consider b=2 as argument of NSA the while cycle should do four iterations and then return s=4. Well...
it doesn't. What's the problem?

(1 / any_integer_greater_than_one == 0)

(1.0 / i)

>

#include<stdio.h>

int NSA(float b){

int i=1;
int s=0;

float sum=0;

while(1){
sum+=(1/i);
s=s+1;
if(sum>=b)
break;
else
i=i+1;
}
return s;
}

int main() {
float a;
int m;
printf("Choose a real number: ");
scanf("%f",&a);
m=NSA(a);
printf("The minimum n for which the armonic series is equal to %f is %d\n ",a,m);
}

/* BEGIN new.c */

#include<stdio.h>

int NSA(double b)
{
int i = 1;
double sum = 1.0;

while (b sum) {
sum += 1.0 / ++i;
}
return i;
}

int main(void)
{
double a;
int m;

printf("Choose a real number: ");
fflush(stdout);
scanf("%lf", &a);
m = NSA(a);
printf("The minimum n for which "
"the armonic series is equal to %f is %d\n ", a, m);
return 0;
}

/* END new.c */
--
pete

[Bingo Bongo]

sum += 1.0 / ++i;

Is there an equivalent code for this piece? I don't know what the / means here.

[Ali Karaali]

On 29 Haziran, 18:26, Bingo Bongo <[e-mail]>
wrote:

* * * * *sum += 1.0 / ++i;

Is there an equivalent code for this piece? I don't know what the / means here.

sum += 1.0 / ++i;

sum = sum + 1.0 / ++i;

First of all i is incremented and the result is divider of 1.0 and
the result of that is adding to sum.

[pete]

Bingo Bongo wrote:

>

> sum += 1.0 / ++i;

Is there an equivalent code for this piece? I don't know what the / means here.

(++i, sum+=((double)1/i));
Here's a clue; you wrote this:

sum+=(1/i);

--
pete

[Mark McIntyre]

Bingo Bongo wrote:

>

> sum += 1.0 / ++i;

Is there an equivalent code for this piece? I don't know what the / means here.

It means divided-by, just as it always does in C.

sum equals sum plus 1.0 divided by (i plus 1)

pete's point is that in C if both the divsor and dividend are integers,
then integer division is performed and integer 1 divided by anything
positive is zero. Hence you need to force floating-point maths by using
1.0 which is a double.

--
Mark McIntyre

CLC FAQ <http://c-faq.com/>
CLC readme: <http://www.ungerhu.com/jxh/clc.welcome.txt>

[Malcolm McLean]

"Bingo Bongo" <bi***************@hotmail.comwrote in message
news:48***********************@reader2.news.tin.it ...

>

> sum += 1.0 / ++i;

Is there an equivalent code for this piece? I don't know what the / means
here.

sum = sum + 1 / (i+1);
i = i + 1;
--
Free games and programming goodies.
http://www.personal.leeds.ac.uk/~bgy1mm

[pete]

Bingo Bongo wrote:

armonic

A lot of times when you write down something
that you heard a Brit say, they're not real words.

--
pete

[pete]

Malcolm McLean wrote:

>
"Bingo Bongo" <bi***************@hotmail.comwrote in message
news:48***********************@reader2.news.tin.it ...

>>

>> sum += 1.0 / ++i;

Is there an equivalent code for this piece? I don't know what the /
means here.

sum = sum + 1 / (i+1);
i = i + 1;

That contains the original error of having integer division
where floating point division is required.

--
pete

[Nick Keighley]

On Jun 29, 5:54*pm, pete <[e-mail]:

Bingo Bongo wrote:

armonic

A lot of times when you write down something
that you heard a Brit say, they're not real words.

what makes you think he's a Brit?

--
Nick Keighley

[pete]

Nick Keighley wrote:

On Jun 29, 5:54 pm, pete <[e-mail]:

>Bingo Bongo wrote:

>>armonic

A lot of times when you write down something
that you heard a Brit say, they're not real words.

what makes you think he's a Brit?

I would say
"a harmonic series". A Brit would be more likely to say
"an harmonic series" with a less pronounced 'h'.

--
pete

[Barry Schwarz]

On Mon, 30 Jun 2008 07:51:31 -0700 (PDT), Nick Keighley
<ni******************@hotmail.comwrote:

>On Jun 29, 5:54*pm, pete <[e-mail]:

>Bingo Bongo wrote:

armonic

A lot of times when you write down something
that you heard a Brit say, they're not real words.

what makes you think he's a Brit?

It was a joke prompted by the typo.
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