Convert two char into one int

[Mariano]

I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

[Kenny McCormack]

In article <8a**********************************@e39g2000hsf. googlegroups.com>,
Mariano <ma**************@gmail.comwrote:

>I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

Continue with:

num[2] = 0;
sscanf(num,"%d",&integ):

[Eric Sosman]

Mariano wrote:

I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????

Assuming `num' is an array of characters (two or more),

integ = (num[0] - '0') * 10 + (num[1] - '0');

will do it.

--
Er*********@sun.com

[Fred Yu]

"Mariano" <ma**************@gmail.com>
:8a**********************************@e39g2000hsf. googlegroups.com...

>I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

integ = atoi(num[0])*10+atoi(num[1]);

[pete]

Fred Yu wrote:

"Mariano" <ma**************@gmail.com>
:8a**********************************@e39g2000hsf. googlegroups.com...

>I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

integ = atoi(num[0])*10+atoi(num[1]);

That's wrong.
num[0] is not a pointer to a string.
atoi takes a pointer to a string as an argument.

int atoi(const char *nptr);

--
pete

[Nick Keighley]

On 26 Jun, 02:15, pete <[e-mail]:

Fred Yu wrote:

"Mariano" <[e-mail]>
:[e-mail]...

I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

integ = atoi(num[0])*10+atoi(num[1]);

That's wrong.
num[0] is not a pointer to a string.

and num may not be a valid string, we don't
know if there's a terminating nul character

atoi takes a pointer to a string as an argument.

and has poor error handling

int atoi(const char *nptr);

--
Nick Keighley