I try to put 8 int bit for example 10100010 into one character of type
char(1 octet) with no hope . Could anyone propose a simple way to do
it? Thank you very much. 13 2437
Anna <pe*********@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of type
char(1 octet) with no hope . Could anyone propose a simple way to do
it? Thank you very much.
It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing.

Ben.
On 15 juin, 11:52, Ben Bacarisse <ben.use...@bsb.me.ukwrote:
Anna <petitmou...@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of type
char(1 octet) with no hope . Could anyone propose a simple way to do
it? Thank you very much.
It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing.

Ben.
thank you Ben. I have bit sequence 01010101.... that I want to
implement into a simulator, but in the simulator, they use a char as a
type of data since each int comprise between 24 octet and one char is
only 1 octet (=8 bits 0 or 1). I guess it will make the simulator run
faster, I'm not sure.
Anna <pe*********@gmail.comwrites:
On 15 juin, 11:52, Ben Bacarisse <ben.use...@bsb.me.ukwrote:
>Anna <petitmou...@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of type
char(1 octet) with no hope . Could anyone propose a simple way to do
it? Thank you very much.
It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing.
 Ben.
Best not quote sig blocks.
thank you Ben. I have bit sequence 01010101.... that I want to
implement into a simulator, but in the simulator, they use a char as a
type of data since each int comprise between 24 octet and one char is
only 1 octet (=8 bits 0 or 1). I guess it will make the simulator run
faster, I'm not sure.
For your information, in C a char is not always an octet and there are
systems where the sizes of the various types can be quite surprising.
I don't think that affects your question, though.
I can't tell if I answered your question. If I did not, you need to
give much more information. Some actual code is often the best way
for people here to see what the problem is.

Ben.
On 15 juin, 12:20, Ben Bacarisse <ben.use...@bsb.me.ukwrote:
Anna <petitmou...@gmail.comwrites:
On 15 juin, 11:52, Ben Bacarisse <ben.use...@bsb.me.ukwrote:
Anna <petitmou...@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of type
char(1 octet) with no hope . Could anyone propose a simple way to do
it? Thank you very much.
It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing.

Ben.
Best not quote sig blocks.
thank you Ben. I have bit sequence 01010101.... that I want to
implement into a simulator, but in the simulator, they use a char as a
type of data since each int comprise between 24 octet and one char is
only 1 octet (=8 bits 0 or 1). I guess it will make the simulator run
faster, I'm not sure.
For your information, in C a char is not always an octet and there are
systems where the sizes of the various types can be quite surprising.
I don't think that affects your question, though.
I can't tell if I answered your question. If I did not, you need to
give much more information. Some actual code is often the best way
for people here to see what the problem is.

Ben.
I think I'll have to try to understand the simulator first. it's a
very complicate network simulator with lots of code :(. I will try to
implement what you suggested and will post the code if I have further
information. thank you very much.
Hi
On Sun, 15 Jun 2008 03:00:50 0700, Anna wrote:
On 15 juin, 11:52, Ben Bacarisse <ben.use...@bsb.me.ukwrote:
>Anna <petitmou...@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of
type char(1 octet) with no hope . Could anyone propose a simple way
to do it? Thank you very much.
It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing.
thank you Ben. I have bit sequence 01010101.... that I want to implement
into a simulator, but in the simulator, they use a char as a type of
data since each int comprise between 24 octet and one char is only 1
octet (=8 bits 0 or 1). I guess it will make the simulator run faster,
I'm not sure.
Do you mean that you have eight integers but that each one has either the
value 1 or 0? In that case, do:
Estce que vousvoulez dire que vous avez huite integers et que chaqun
d'entre eux a le valeur 1 ou 0? En ce cas, faitez:
int integers[8];
unsigned char character;
character= ( integers[0] ? (1 << 0) : 0 )
 ( integers[1] ? (1 << 1) : 0 )
 ( integers[2] ? (1 << 2) : 0 )
 ( integers[3] ? (1 << 3) : 0 )
 ( integers[4] ? (1 << 4) : 0 )
 ( integers[5] ? (1 << 5) : 0 )
 ( integers[6] ? (1 << 6) : 0 )
 ( integers[7] ? (1 << 7) : 0 );
Actually this works if the integers have the value 0 or non0. If you
are certain that they can only be 1 or 0, the following may be faster:
Ceci marche si les integers ont les valeurs 0 ou non0. Si vous etez
certain que ils n'ont que 1 ou 0, le cidessus peutetre plus vite:
character= (integers[0] << 0)
 ( integers[1] << 1)
 ( integers[2] << 2)
 ( integers[3] << 3)
 ( integers[4] << 4)
 ( integers[5] << 5)
 ( integers[6] << 6)
 ( integers[7] << 7);
HTH
viza
viza wrote:
Anna wrote:
>Ben Bacarisse <ben.use...@bsb.me.ukwrote:
>>Anna <petitmou...@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of type char(1 octet) with no hope . Could anyone propose a simple way to do it? Thank you very much.
It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing.
thank you Ben. I have bit sequence 01010101.... that I want to implement into a simulator, but in the simulator, they use a char as a type of data since each int comprise between 24 octet and one char is only 1 octet (=8 bits 0 or 1). I guess it will make the simulator run faster, I'm not sure.
Do you mean that you have eight integers but that each one has
either the value 1 or 0? In that case, do:
Estce que vousvoulez dire que vous avez huite integers et que
chaqun d'entre eux a le valeur 1 ou 0? En ce cas, faitez:
int integers[8];
unsigned char character;
character= ( integers[0] ? (1 << 0) : 0 )
 ( integers[1] ? (1 << 1) : 0 )
 ( integers[2] ? (1 << 2) : 0 )
 ( integers[3] ? (1 << 3) : 0 )
 ( integers[4] ? (1 << 4) : 0 )
 ( integers[5] ? (1 << 5) : 0 )
 ( integers[6] ? (1 << 6) : 0 )
 ( integers[7] ? (1 << 7) : 0 );
Actually this works if the integers have the value 0 or non0.
If you are certain that they can only be 1 or 0, the following
may be faster:
Ceci marche si les integers ont les valeurs 0 ou non0. Si vous
etez certain que ils n'ont que 1 ou 0, le cidessus peutetre
plus vite:
character= (integers[0] << 0)
 ( integers[1] << 1)
 ( integers[2] << 2)
 ( integers[3] << 3)
 ( integers[4] << 4)
 ( integers[5] << 5)
 ( integers[6] << 6)
 ( integers[7] << 7);
What gives you the idea that Anna speaks French?

[mail]: Chuck F (cbfalconer at maineline dot net)
[page]: <http://cbfalconer.home.att.net>
Try the download section.
** Posted from http://www.teranews.com **
CBFalconer wrote:
What gives you the idea that Anna speaks French?
Her email address petitmuoton?
CBFalconer wrote:
viza wrote:
>Anna wrote:
>>Ben Bacarisse <ben.use...@bsb.me.ukwrote: Anna <petitmou...@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of type char(1 octet) with no hope . Could anyone propose a simple way to do it? Thank you very much. It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing. thank you Ben. I have bit sequence 01010101.... that I want to implement into a simulator, but in the simulator, they use a char as a type of data since each int comprise between 24 octet and one char is only 1 octet (=8 bits 0 or 1). I guess it will make the simulator run faster, I'm not sure.
Do you mean that you have eight integers but that each one has either the value 1 or 0? In that case, do:
Estce que vousvoulez dire que vous avez huite integers et que chaqun d'entre eux a le valeur 1 ou 0? En ce cas, faitez:
int integers[8]; unsigned char character;
character= ( integers[0] ? (1 << 0) : 0 )  ( integers[1] ? (1 << 1) : 0 )  ( integers[2] ? (1 << 2) : 0 )  ( integers[3] ? (1 << 3) : 0 )  ( integers[4] ? (1 << 4) : 0 )  ( integers[5] ? (1 << 5) : 0 )  ( integers[6] ? (1 << 6) : 0 )  ( integers[7] ? (1 << 7) : 0 );
Actually this works if the integers have the value 0 or non0. If you are certain that they can only be 1 or 0, the following may be faster:
Ceci marche si les integers ont les valeurs 0 ou non0. Si vous etez certain que ils n'ont que 1 ou 0, le cidessus peutetre plus vite:
character= (integers[0] << 0)  ( integers[1] << 1)  ( integers[2] << 2)  ( integers[3] << 3)  ( integers[4] << 4)  ( integers[5] << 5)  ( integers[6] << 6)  ( integers[7] << 7);
What gives you the idea that Anna speaks French?
Calling herself 'petitmouton' is a clue.

Joe Wright
"Everything should be made as simple as possible, but not simpler."
 Albert Einstein 
"viza" <to******@gmil.comwrote in message
On Sun, 15 Jun 2008 03:00:50 0700, Anna wrote:
Estce que vousvoulez dire que vous avez huite integers et que chaqun
d'entre eux a le valeur 1 ou 0? En ce cas, faitez:
Crosspost French to comp.lang.c.fr

Free games and programming goodies. http://www.personal.leeds.ac.uk/~bgy1mm
"Anna" <pe*********@gmail.comwrote in message
thank you Ben. I have bit sequence 01010101.... that I want to
implement into a simulator, but in the simulator, they use a char as a
type of data since each int comprise between 24 octet and one char is
only 1 octet (=8 bits 0 or 1). I guess it will make the simulator run
faster, I'm not sure.
char inputchar = 0x55; will set the variable inputchar to 01010101

Free games and programming goodies. http://www.personal.leeds.ac.uk/~bgy1mm
On 15 Jun 2008 at 15:27, Malcolm McLean wrote:
"viza" <to******@gmil.comwrote in message
>Estce que vousvoulez dire que vous avez huite integers et que chaqun d'entre eux a le valeur 1 ou 0? En ce cas, faitez:
Crosspost French to comp.lang.c.fr
Describing that as French is more than a little generous...
On 15 juin, 13:33, viza <tom.v...@gmil.comwrote:
Hi
On Sun, 15 Jun 2008 03:00:50 0700, Anna wrote:
On 15 juin, 11:52, Ben Bacarisse <ben.use...@bsb.me.ukwrote:
Anna <petitmou...@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of
type char(1 octet) with no hope . Could anyone propose a simple way
to do it? Thank you very much.
It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing.
thank you Ben. I have bit sequence 01010101.... that I want to implement
into a simulator, but in the simulator, they use a char as a type of
data since each int comprise between 24 octet and one char is only 1
octet (=8 bits 0 or 1). I guess it will make the simulator run faster,
I'm not sure.
Do you mean that you have eight integers but that each one has either the
value 1 or 0? In that case, do:
Estce que vousvoulez dire que vous avez huite integers et que chaqun
d'entre eux a le valeur 1 ou 0? En ce cas, faitez:
int integers[8];
unsigned char character;
character= ( integers[0] ? (1 << 0) : 0 )
 ( integers[1] ? (1 << 1) : 0 )
 ( integers[2] ? (1 << 2) : 0 )
 ( integers[3] ? (1 << 3) : 0 )
 ( integers[4] ? (1 << 4) : 0 )
 ( integers[5] ? (1 << 5) : 0 )
 ( integers[6] ? (1 << 6) : 0 )
 ( integers[7] ? (1 << 7) : 0 );
Actually this works if the integers have the value 0 or non0. If you
are certain that they can only be 1 or 0, the following may be faster:
Ceci marche si les integers ont les valeurs 0 ou non0. Si vous etez
certain que ils n'ont que 1 ou 0, le cidessus peutetre plus vite:
character= (integers[0] << 0)
 ( integers[1] << 1)
 ( integers[2] << 2)
 ( integers[3] << 3)
 ( integers[4] << 4)
 ( integers[5] << 5)
 ( integers[6] << 6)
 ( integers[7] << 7);
HTH
viza
Bonjour Viza,
Bien joué, je parle français aussi :) merce beaucoup pour ta réponse.
Je trouve très intéressant et je pense que je vais essayer
d'implementer ce ci sur mon programme. Merci, merci, merci
Anna
On 15 juin, 13:33, viza <tom.v...@gmil.comwrote:
Hi
On Sun, 15 Jun 2008 03:00:50 0700, Anna wrote:
On 15 juin, 11:52, Ben Bacarisse <ben.use...@bsb.me.ukwrote:
Anna <petitmou...@gmail.comwrites:
I try to put 8 int bit for example 10100010 into one character of
type char(1 octet) with no hope . Could anyone propose a simple way
to do it? Thank you very much.
It would help is we saw what you did. I would write:
unsigned char c = 0xA2; /* Hex A2 is 1010 0010 */
Not that unsigned char is almost always safer for this sort of thing.
thank you Ben. I have bit sequence 01010101.... that I want to implement
into a simulator, but in the simulator, they use a char as a type of
data since each int comprise between 24 octet and one char is only 1
octet (=8 bits 0 or 1). I guess it will make the simulator run faster,
I'm not sure.
Do you mean that you have eight integers but that each one has either the
value 1 or 0? In that case, do:
Estce que vousvoulez dire que vous avez huite integers et que chaqun
d'entre eux a le valeur 1 ou 0? En ce cas, faitez:
int integers[8];
unsigned char character;
character= ( integers[0] ? (1 << 0) : 0 )
 ( integers[1] ? (1 << 1) : 0 )
 ( integers[2] ? (1 << 2) : 0 )
 ( integers[3] ? (1 << 3) : 0 )
 ( integers[4] ? (1 << 4) : 0 )
 ( integers[5] ? (1 << 5) : 0 )
 ( integers[6] ? (1 << 6) : 0 )
 ( integers[7] ? (1 << 7) : 0 );
Actually this works if the integers have the value 0 or non0. If you
are certain that they can only be 1 or 0, the following may be faster:
Ceci marche si les integers ont les valeurs 0 ou non0. Si vous etez
certain que ils n'ont que 1 ou 0, le cidessus peutetre plus vite:
character= (integers[0] << 0)
 ( integers[1] << 1)
 ( integers[2] << 2)
 ( integers[3] << 3)
 ( integers[4] << 4)
 ( integers[5] << 5)
 ( integers[6] << 6)
 ( integers[7] << 7);
HTH
viza
Bonjour Viza,
Oui, je parle français aussi :) merci beaucoup pour ton aide. Ton
programme me semble très intéressant, je vais essayer d'implementer ce
ci sur le simulateur. Merci beaucoup.
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