How to avoid a lot of switch case

[silusilusilu]

I wrote ,as homework, a program that displays words after key pressed.
So, if letter 'A' is pressed, the word 'dog' appears; if letter 'B' is
pressed 'cat' appears; if letter 'a' is pressed 'apple' appears; and
so on...
I wrote this program with a lot of switch case, so i want to obtain a
smaller program (if possible)...can you help me?

[Szabolcs Borsanyi]

On Thu, May 29, 2008 at 11:26:34PM -0700, si**********@gmail.com wrote:

I wrote ,as homework, a program that displays words after key pressed.
So, if letter 'A' is pressed, the word 'dog' appears; if letter 'B' is
pressed 'cat' appears; if letter 'a' is pressed 'apple' appears; and
so on...
I wrote this program with a lot of switch case, so i want to obtain a
smaller program (if possible)...can you help me?

What you would like to do is to map integers to strings.

How about an array?
const char *my_lovely_words[UCHAR_MAX];

Please stop reading here, try to write the program, and then you may continue.

my_lovely_words['a']="apple";
....
But I do not see how that would save you much keystrokes.

In C99 you can have named initialisers
const char *my_lovely_words[]={
['A']="dog",
['a']="apple",
};

Szabolcs

[vippstar]

On May 30, 9:52 am, Szabolcs Borsanyi <[e-mail]:

On Thu, May 29, 2008 at 11:26:34PM -0700, [e-mail] wrote:

I wrote ,as homework, a program that displays words after key pressed.
So, if letter 'A' is pressed, the word 'dog' appears; if letter 'B' is
pressed 'cat' appears; if letter 'a' is pressed 'apple' appears; and
so on...
I wrote this program with a lot of switch case, so i want to obtain a
smaller program (if possible)...can you help me?

What you would like to do is to map integers to strings.

How about an array?
const char *my_lovely_words[UCHAR_MAX];

Please stop reading here, try to write the program, and then you may continue.

my_lovely_words['a']="apple";

And what if 'a' has the value 4325? It would waste a lot of space.
Here's another solution:

const char *my_lovely_words[] = { ... };
const char *p, str[] = "#Az";
int c;
....
if(p = strchr(str, c)) != NULL) printf("%c = %s\n", c,
my_lovely_words[p - str]);