What is the difference between: int a (*daytab)[13] and int a*daytab[13]

[magicman]

thx

[=?ISO-8859-1?Q?Tom=E1s_=D3_h=C9ilidhe?=]

int (*)[13] Pointer to an array of 13 int's.
int *[13] Array of 13 pointers to int's.

[Bartc]

"magicman" <ir*********@gmail.comwrote in message
news:11**********************************@k13g2000 hse.googlegroups.com..

[What is the difference between: int a (*daytab)[13] and int a
*daytab[13]]

As written: nothing, they're both syntax errors.

On the other hand, int (*daytab)[13] is a pointer to an array of 13 ints.

While int *daytab[13] is an array of 13 pointers to ints.

(Thanks to a program cdecl.exe I've just downloaded. Otherwise I wouldn't
have a clue either. And the existence of such a program suggests I'm not
alone!)

--
Bartc

[santosh]

magicman wrote:

What is the difference between: int a (*daytab)[13] and int a
*daytab[13]
thx

In a declaration the first one declares daytab as a pointer to an array
of 13 ints. The second declares daytab as an array of 13 int*.

For the first one

daytab[n]

will be of type int and for the second one

daytab[n]

will be of type int*.

PS. For 0 <= n <= 12 of course.

[Ben Bacarisse]

santosh <sa*********@gmail.comwrites:

magicman wrote:

>What is the difference between: int a (*daytab)[13] and int a
*daytab[13]
thx

In a declaration the first one declares daytab as a pointer to an array
of 13 ints. The second declares daytab as an array of 13 int*.

I guess you are ignoring the "a" in both!

For the first one

daytab[n]

will be of type int

It will be of type "array of 13 int". It will be converted to an int
pointer in most contexts hence, I suspect, the confusion.

and for the second one

daytab[n]

will be of type int*.

Yes, in both cases daytab[n] could be further subscripted or passed to
function that expects and int *.

--
Ben.

[santosh]

Ben Bacarisse wrote:

santosh <sa*********@gmail.comwrites:

>magicman wrote:

>>What is the difference between: int a (*daytab)[13] and int a
*daytab[13]
thx

In a declaration the first one declares daytab as a pointer to an
array of 13 ints. The second declares daytab as an array of 13 int*.

I guess you are ignoring the "a" in both!

Oops! I'm starting to really believe the research indications that the
brain "reads" what it "wants to read", or "completes" sentences from
partially reading them. Thanks once again for the correction.

>For the first one

daytab[n]

will be of type int

It will be of type "array of 13 int". It will be converted to an int
pointer in most contexts hence, I suspect, the confusion.

>and for the second one

daytab[n]

will be of type int*.

Yes, in both cases daytab[n] could be further subscripted or passed to
function that expects and int *.