On Jun 23, 1:51 pm, Selvam <kalaiselva...@gmail.comwrote:
I am getting exponent value when doing float arithmetic in
C++. Instead of that I need accurate value.
I'm not sure what you mean by "accurate value". You're
probablyl getting a reasonably accurate value in the results,
but just not formatting it correctly.
float amount = 0.0f;
float x = 0.99999976f;
amount= 1.0f - x;
I am getting amount as 2.3841858e-007 instead of 0.00000024
Which is probably more accurate. (Note that despite what you
wrote, you certainly never had a float value of 0.99999976.) Of
course, if what you want is the value rounded to 8 points after
the decimal, then you have to tell the computer to output it
like that:
std::cout.setf( std::ios::fixed, std::ios::floatfield ) ;
std::cout.precision( 8 ) ;
std::cout << x ;
Typically, of course, you'll wrap those first two statements in
some sort of application specific manipulator, and write
something like:
std::cout << appliFmt << x ;
(Also: float is only good for six or seven decimal digits
accuracy; you probably want to consider double.)
Can anyone tell what will be the solution for this problem???
Note : I am getting correct value in C#.Net but not in C++
I'm pretty sure that you're getting the same results in both
cases. But the default formatting isn't necessarily the same.
--
James Kanze (GABI Software) email:ja*********@gmail.com
Conseils en informatique orientée objet/
Beratung in objektorientierter Datenverarbeitung
9 place Sémard, 78210 St.-Cyr-l'École, France, +33 (0)1 30 23 00 34