double format specification

[JK]

The following is a sample program I wrote..

float fTick = 0.0001;
float fLotSize = 100;
int iDeno = 10000;

double dVal;
double dInt;

dInt = fTick * fLotSize;
dVal = fTick * fLotSize * iDeno;

printf ("dVal : %g dInt : %g fTick: %g\n", dVal, dInt, fTick);

This is printing the output as :

dVal : 100 dInt : 0.01 fTick: 1e-04

If I use the format type "f" instead of "g" it prints the following
output

dVal : 99.999997 dInt : 0.010000 fTick: 0.000100

Here is my doubt. I always want the output in dddd.dddd ( where
dddd is one more decimal digits. It can go upto 10)
What should I give as the format specification to print the ouput in
the dddd.dddd format ?
Please help to resolve this problem..
FYI: I use g++ compiler (linux-gnu-2.4).

[shan_rish]

On Jun 9, 3:13 pm, JK <[e-mail]:

The following is a sample program I wrote..

float fTick = 0.0001;
float fLotSize = 100;
int iDeno = 10000;

double dVal;
double dInt;

dInt = fTick * fLotSize;
dVal = fTick * fLotSize * iDeno;

printf ("dVal : %g dInt : %g fTick: %g\n", dVal, dInt, fTick);

This is printing the output as :

dVal : 100 dInt : 0.01 fTick: 1e-04

If I use the format type "f" instead of "g" it prints the following
output

dVal : 99.999997 dInt : 0.010000 fTick: 0.000100

Here is my doubt. I always want the output in dddd.dddd ( where
dddd is one more decimal digits. It can go upto 10)
What should I give as the format specification to print the ouput in
the dddd.dddd format ?
Please help to resolve this problem..
FYI: I use g++ compiler (linux-gnu-2.4).

The printf is a C language function and not a C++ function. Use cout
instead.

[Gianni Mariani]

sh*******@yahoo.com wrote:
...

The printf is a C language function and not a C++ function. Use cout
instead.

printf is still part of C++ as well. Still, it is better to use
std::ostream.