Inheriting from a typedef that is inside another class

[itaj sherman]

The following does not compile on my VC6. Is it standard?
#include <iostream>

class Base
{
public:
explicit Base()
{
std::cout << "Base:ctor()" << "\n";
}

};
class Scope
{
public:
typedef Base BaseInScope;
};

class Derived:
public Scope::BaseInScope
{
public:
explicit Derived()
:
Scope::BaseInScope()
{
std::cout << "Derived:ctor()" << "\n";
}
};
D:\code\Test\Test\Test.cpp(39) : error C2614: 'Derived' : illegal
member initialization: 'BaseInScope' is not a base or member

The following fixes the problem:
class Derived:
public Scope::BaseInScope
{
public:
typedef Scope::BaseInScope MyBase

explicit Derived()
:
MyBase()
{
std::cout << "Derived:ctor()" << "\n";
}
};
and also:
class Derived:
public Scope::BaseInScope
{
public:
explicit Derived()
:
Base()
{
std::cout << "Derived:ctor()" << "\n";
}
};

[=?utf-8?Q?David_C=C3=B4me?=]

On Sun, 25 May 2008 16:20:32 +0200, itaj sherman <it*********@gmail.com>
wrote:

The following does not compile on my VC6. Is it standard?

Change it for VS C++ 2008.

#include <iostream>

class Base
{
public:
explicit Base()
{
std::cout << "Base:ctor()" << "\n";
}

};
class Scope
{
public:
typedef Base BaseInScope;
};

class Derived:
public Scope::BaseInScope
{
public:
explicit Derived()
:
Scope::BaseInScope()
{
std::cout << "Derived:ctor()" << "\n";
}
};

compile perfectly with g++

[Frank Birbacher]

Hi!

Alf P. Steinbach schrieb:

<quote>
Comeau C/C++ 4.3.10.1 (May 7 2008 20:26:48) for ONLINE_EVALUATION_BETA1
Copyright 1988-2008 Comeau Computing. All rights reserved.
MODE:strict errors C++ noC++0x_extensions
In strict mode, with -tused, Compile succeeded (but remember, the Comeau
online compiler does not link).
</quote>

In short this means "it is standard". :)

Well, I wonder what would do the "explicit" specification to the default
ctor? There isn't even a warning about it which makes me wonder if there
is any effect. Is there?

Frank