Hi,
If i have a std::vector containing pointers, then iterate through the
vector and im slightly confused as to how i use the item from the
iterator?
for example,
vector<MyClass*myvector;
....
vector<MyClass*>::iterator it;
for(it = myvector.begin(); it < myvector.end(); it++)
{
// This doesn't work,
**it->myclassmember();
}
What am i doing wrong? I thought the iterator is a pointer to a
pointer in this case?
Thanks alot for any help,
8  1764 
On 2008-04-22 19:25, JackC wrote:
Hi,
If i have a std::vector containing pointers, then iterate through the
vector and im slightly confused as to how i use the item from the
iterator?
for example,
vector<MyClass*myvector;
...
vector<MyClass*>::iterator it;
for(it = myvector.begin(); it < myvector.end(); it++)
{
// This doesn't work,
**it->myclassmember();
}
What am i doing wrong? I thought the iterator is a pointer to a
pointer in this case?
Use either
(*it)->myclassmember();
or
(**it).myclassmember();
--
Erik Wikström
On 22 Apr, 18:50, Erik Wikström <Erik-wikst...@telia.comwrote:
On 2008-04-22 19:25, JackC wrote:
Hi,
If i have a std::vector containing pointers, then iterate through the
vector and im slightly confused as to how i use the item from the
iterator?
for example,
vector<MyClass*myvector;
...
vector<MyClass*>::iterator it;
for(it = myvector.begin(); it < myvector.end(); it++)
{
// This doesn't work,
**it->myclassmember();
}
What am i doing wrong? I thought the iterator is a pointer to a
pointer in this case?
Use either
(*it)->myclassmember();
or
(**it).myclassmember();
--
Erik Wikström
Thanks very much, works fine.
On 2008-04-22 13:50:53 -0400, Erik Wikström <Er***********@telia.comsaid:
On 2008-04-22 19:25, JackC wrote:
>Hi,
If i have a std::vector containing pointers, then iterate through the
vector and im slightly confused as to how i use the item from the
iterator?
for example,
vector<MyClass*myvector;
...
vector<MyClass*>::iterator it;
for(it = myvector.begin(); it < myvector.end(); it++)
{
// This doesn't work,
**it->myclassmember();
}
What am i doing wrong? I thought the iterator is a pointer to a
pointer in this case?
Use either
(*it)->myclassmember();
or
(**it).myclassmember();
Or
it->myclassmember();
--
Pete
Roundhouse Consulting, Ltd. ( www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
( www.petebecker.com/tr1book)
On Apr 22, 8:36 pm, Pete Becker <p...@versatilecoding.comwrote:
On 2008-04-22 13:50:53 -0400, Erik Wikström <Erik-wikst...@telia.comsaid:
...
Or
it->myclassmember();
...
Is that possible? myvector is a vector of pointers.
Regards.
On 2008-04-22 16:38:22 -0400, al**********@gmail.com said:
On Apr 22, 8:36 pm, Pete Becker <p...@versatilecoding.comwrote:
>On 2008-04-22 13:50:53 -0400, Erik Wikström <Erik-wikst...@telia.comsa
id:
...
>Or
it->myclassmember();
...
Is that possible? myvector is a vector of pointers.
Try it.
--
Pete
Roundhouse Consulting, Ltd. ( www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
( www.petebecker.com/tr1book)
<al**********@gmail.comwrote in message
On Apr 22, 8:36 pm, Pete Becker <p...@versatilecoding.comwrote:
>On 2008-04-22 13:50:53 -0400, Erik Wikström <Erik-wikst...@telia.com>
said:
it->myclassmember();
Is that possible? myvector is a vector of pointers.
No. Probably Pete was in a hurry.
-- http://techytalk.googlepages.com
Pete Becker wrote:
On 2008-04-22 16:38:22 -0400, al**********@gmail.com said:
>On Apr 22, 8:36 pm, Pete Becker <p...@versatilecoding.comwrote:
>>On 2008-04-22 13:50:53 -0400, Erik Wikström <Erik-wikst...@telia.comsa
id:
...
>>Or
it->myclassmember();
...
Is that possible? myvector is a vector of pointers.
Try it.
Ant you'll get a compile error!
--
Ian Collins.
On 2008-04-22 17:14:59 -0400, Ian Collins <ia******@hotmail.comsaid:
Pete Becker wrote:
>On 2008-04-22 16:38:22 -0400, al**********@gmail.com said:
>>On Apr 22, 8:36 pm, Pete Becker <p...@versatilecoding.comwrote:
On 2008-04-22 13:50:53 -0400, Erik Wikström <Erik-wikst...@telia.comsa
id:
...
Or
it->myclassmember();
...
Is that possible? myvector is a vector of pointers.
Try it.
Ant you'll get a compile error!
Yup. There's an extra level of indirection that I overlooked.
--
Pete
Roundhouse Consulting, Ltd. ( www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
( www.petebecker.com/tr1book) This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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