base class and derived class having same variable

[Rahul]

Hi Everyone,

I have the following code,

class AA
{
public:
int i;
};

class B : public AA
{
public : int i;
};

int main()
{
B obj;
obj.AA::i = 10;
obj.B::i = 20;
cout<<obj.AA::i<< " " <<obj.B::i<<endl;
obj.i =
10; //
Isn't this ambiguous?
cout<<obj.AA::i<< " " <<obj.B::i<<endl;
return(0);
}

I expected a compilation error when obj.i is used as there are two
versions if i available in class B. How does the compiler manage to
resolve the reference to the correct i?

Thanks in advance ! ! !

[raof01]

Hello Rahul,

Isn't this ambiguous?
cout<<obj.AA::i<< " " <<obj.B::i<<endl;
return(0);
}

No. This is about name hiding. The scope of derived class is nested in that
of base class. So i in B hides that in AA. You can use obj.i to access B::i,
and use AA::i or using directive to make AA::i visible.

raof01
mailto:ra****@gmail.com
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