accessing parent class method

[ArbolOne]

In my program I am using two classes foo1, the parent class, and foo2
the child class!
foo2 has overloaded inserter and extractor operator, but so does foo1!
How can I access foo1 inserter or extractor?
Thanks

[Victor Bazarov]

ArbolOne wrote:

In my program I am using two classes foo1, the parent class, and foo2
the child class!
foo2 has overloaded inserter and extractor operator, but so does foo1!
How can I access foo1 inserter or extractor?

Post your code. It is easier when there is substance to the discussion.

Meanwhile, here is the example:

struct foo {
void foobar();
};

struct bar : foo {
void foobar();
};

int main() {
bar b;
b.foobar(); // calls bar::foobar
b.foo::foobar(); // call foo::foobar
}

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

[=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?=]

On 2008-06-01 03:07, Victor Bazarov wrote:

ArbolOne wrote:

>In my program I am using two classes foo1, the parent class, and foo2
the child class!
foo2 has overloaded inserter and extractor operator, but so does foo1!
How can I access foo1 inserter or extractor?

Post your code. It is easier when there is substance to the discussion.

Meanwhile, here is the example:

struct foo {
void foobar();
};

struct bar : foo {
void foobar();
};

int main() {
bar b;
b.foobar(); // calls bar::foobar
b.foo::foobar(); // call foo::foobar
}

I would call it bad style to explicitly call a parent's implemenetation
of a function (and bad design if you have to), unless it is done in the
child's implementation of the same function:

#include<iostream>

struct foo1 {
virtual void foobar() {
std::cout << "foo1\n";
}
};

struct foo2 : public foo1 {
virtual void foobar() {
std::cout << "foo2\n";
foo1::foobar(); // Call foo1's foobar()
}
};

int main() {
foo1* f = new foo1();
f->foobar();
delete f;
f = new foo2();
f->foobar();
}

--
Erik Wikström

[ArbolOne]

On Jun 1, 3:57 am, Erik Wikström <[e-mail]:

On 2008-06-01 03:07, Victor Bazarov wrote:

ArbolOne wrote:

In my program I am using two classes foo1, the parent class, and foo2
the child class!
foo2 has overloaded inserter and extractor operator, but so does foo1!
How can I access foo1 inserter or extractor?

Post your code. It is easier when there is substance to the discussion.

Meanwhile, here is the example:

struct foo {
void foobar();
};

struct bar : foo {
void foobar();
};

int main() {
bar b;
b.foobar(); // calls bar::foobar
b.foo::foobar(); // call foo::foobar
}

I would call it bad style to explicitly call a parent's implemenetation
of a function (and bad design if you have to), unless it is done in the
child's implementation of the same function:

#include<iostream>

struct foo1 {
virtual void foobar() {
std::cout << "foo1\n";
}

};

struct foo2 : public foo1 {
virtual void foobar() {
std::cout << "foo2\n";
foo1::foobar(); // Call foo1's foobar()
}

};

int main() {
foo1* f = new foo1();
f->foobar();
delete f;
f = new foo2();
f->foobar();

}

--
Erik Wikström

I got it now!
Thanks.