Hi all,
Are function pointer and pointer to a function same ?
How do we declare a function pointer ?
How to declare an array of function pointers ?
Can you please give some examples for these.
Thanks,
4  1516  pr****************@gmail.com wrote:
Hi all,
Are function pointer and pointer to a function same ?
Yes.
How do we declare a function pointer ?
It depends on the type of function you want to point to. For example, to
declare fp as a pointer to a function taking char * and returning int,
you'd say:
int (*fp)(char *);
All parenthesis () are necessary. If you say:
int *fp(char *);
then you're declaring fp as a function taking 'char *' and returning
'int *'.
How to declare an array of function pointers ?
When things get more complicated, such as arrays of function pointers,
or pointers to functions taking pointers to functions and returning a
pointer to function, you can still declare them directly, but you can
also do it in stages using typedefs. There's a wonderful example in the
FAQ, question 1.21.
Philip
On Apr 10, 4:17*pm, Philip Potter <p...@doc.ic.ac.ukwrote:
prashant.khade1...@gmail.com wrote:
Hi all,
Are function pointer and pointer to a function same ?
Yes.
How do we declare a function pointer ?
It depends on the type of function you want to point to. For example, to
declare fp as a pointer to a function taking char * and returning int,
you'd say:
int (*fp)(char *);
All parenthesis () are necessary. If you say:
int *fp(char *);
then you're declaring fp as a function taking 'char *' and returning
'int *'.
How to declare an array of function pointers ?
When things get more complicated, such as arrays of function pointers,
or pointers to functions taking pointers to functions and returning a
pointer to function, you can still declare them directly, but you can
also do it in stages using typedefs. There's a wonderful example in the
FAQ, question 1.21.
Philip
thanks for your help...
I need to know about declaring array of function pointers and how to
use them pr****************@gmail.com wrote:
On Apr 10, 4:17 pm, Philip Potter <p...@doc.ic.ac.ukwrote:
>prashant.khade1...@gmail.com wrote:
>>How to declare an array of function pointers ?
When things get more complicated, such as arrays of function pointers,
or pointers to functions taking pointers to functions and returning a
pointer to function, you can still declare them directly, but you can
also do it in stages using typedefs. There's a wonderful example in the
FAQ, question 1.21.
Philip
thanks for your help...
I need to know about declaring array of function pointers and how to
use them
I have already answered your question. I have quoted my answer above. If
you still don't understand, ask more specific questions - if you ask the
same question again, I can't tell which bit of my answer you haven't
understood.
Groovy hepcat Philip Potter was jivin' in comp.lang.c on Fri, 11 Apr
2008 5:30 pm. It's a cool scene! Dig it. pr****************@gmail.com wrote:
>On Apr 10, 4:17 pm, Philip Potter <p...@doc.ic.ac.ukwrote:
>>prashant.khade1...@gmail.com wrote:
How to declare an array of function pointers ?
When things get more complicated, such as arrays of function
pointers, or pointers to functions taking pointers to functions and
returning a pointer to function, you can still declare them
directly, but you can also do it in stages using typedefs. There's a
wonderful example in the FAQ, question 1.21.
Philip
thanks for your help...
I need to know about declaring array of function pointers and how to
use them
I have already answered your question. I have quoted my answer above.
If you still don't understand, ask more specific questions - if you
ask the same question again, I can't tell which bit of my answer you
haven't understood.
True the OP *could* declare an array of pointer to function by using
typedef, but I think he wants to declare it directly. It's easy enough.
You haven't forgotten how to do it, have you, Phil? :)
int (*fpa[10])(int);
This declares an array of 10 pointers to function taking and int and
returning an int.
--
Dig the sig!
----------- Peter 'Shaggy' Haywood ------------
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