Question on adding strings

[C++ Newbie]

Hi,

Consider the following program from "Accelerated C++", Koenig & Moo
[2004]:

Case [1]:
=====================================
#include <iostream>
#include <string>

int main()
{

// Ex 1-2
const std::string exclam = "!";
const std::string message2 = "Hello" + ", world" + exclam ;
std::cout << message2;
std::cout << std::endl;
return 0;
}
=====================================

The above fails to compile with the error:
1-3.cpp: In function 'int main()':
1-3.cpp:18: error: invalid operands of types 'const char [6]' and
'const char [8]' to binary 'operator+'

(Line numbers are a bit off as I snipped out irrelevant code)

If we move around the string addition a bit to a less sensible
arrangement:
Case 2:
=======================================
#include <iostream>
#include <string>

int main()
{

// Ex 1-1
const std::string hello = "Hello";
std::cout << hello;
std::cout << std::endl;

const std:: string message = hello + ", world" + "!";
std::cout << message;
std::cout << std::endl;

// Ex 1-2
const std::string exclam = "!";
const std::string message2 = "Hello" + exclam + ", world" ;
std::cout << message2;
std::cout << std::endl;

return 0;
}
====================================

The above compiles and runs.

Why does changing the arrangement of message2 make such a big
difference?

Thanks for any input.

[Christopher]

On Mar 31, 9:50 am, "C++ Newbie" <[e-mail]:

Hi,

Consider the following program from "Accelerated C++", Koenig & Moo
[2004]:

Case [1]:
=====================================
#include <iostream>
#include <string>

int main()
{

// Ex 1-2
const std::string exclam = "!";
const std::string message2 = "Hello" + ", world" + exclam ;
std::cout << message2;
std::cout << std::endl;
return 0;}

=====================================

The above fails to compile with the error:
1-3.cpp: In function 'int main()':
1-3.cpp:18: error: invalid operands of types 'const char [6]' and
'const char [8]' to binary 'operator+'

(Line numbers are a bit off as I snipped out irrelevant code)

If we move around the string addition a bit to a less sensible
arrangement:
Case 2:
=======================================
#include <iostream>
#include <string>

int main()
{

// Ex 1-1
const std::string hello = "Hello";
std::cout << hello;
std::cout << std::endl;

const std:: string message = hello + ", world" + "!";
std::cout << message;
std::cout << std::endl;

// Ex 1-2
const std::string exclam = "!";
const std::string message2 = "Hello" + exclam + ", world" ;
std::cout << message2;
std::cout << std::endl;

return 0;}

====================================

The above compiles and runs.

Why does changing the arrangement of message2 make such a big
difference?

Thanks for any input.

Because, char* does not have operator +(const char* &) defined, while
std::string does.

[Bo Persson]

C++ Newbie wrote:

Hi,

Consider the following program from "Accelerated C++", Koenig & Moo
[2004]:

Case [1]:
=====================================
#include <iostream>
#include <string>

int main()
{

// Ex 1-2
const std::string exclam = "!";
const std::string message2 = "Hello" + ", world" + exclam ;
std::cout << message2;
std::cout << std::endl;
return 0;
}
=====================================

The above fails to compile with the error:
1-3.cpp: In function 'int main()':
1-3.cpp:18: error: invalid operands of types 'const char [6]' and
'const char [8]' to binary 'operator+'

Like the compiler says, there is no operator+ for string literals. Why
would you need one?

You can write either:
const std::string message2 = "Hello, world" + exclam ;
or (with no plus)
const std::string message2 = "Hello" ", world" + exclam ;

and it just works.
Bo Persson

[C++ Newbie]

On 31 Mar, 17:02, "Bo Persson" <[e-mail]:

C++ Newbie wrote:

Hi,

Consider the following program from "Accelerated C++", Koenig & Moo
[2004]:

Case [1]:
=====================================
#include <iostream>
#include <string>

int main()
{

// Ex 1-2
const std::string exclam = "!";
const std::string message2 = "Hello" + ", world" + exclam ;
std::cout << message2;
std::cout << std::endl;
return 0;
}
=====================================

The above fails to compile with the error:
1-3.cpp: In function 'int main()':
1-3.cpp:18: error: invalid operands of types 'const char [6]' and
'const char [8]' to binary 'operator+'

Like the compiler says, there is no operator+ for string literals. Why
would you need one?

You can write either:
const std::string message2 = "Hello, world" + exclam ;
or (with no plus)
const std::string message2 = "Hello" ", world" + exclam ;

and it just works.

Bo Persson

OK thanks guys!

[Alf P. Steinbach]

* C++ Newbie:

>
Consider the following program from "Accelerated C++", Koenig & Moo
[2004]:

Case [1]:
=====================================
#include <iostream>
#include <string>

int main()
{

// Ex 1-2
const std::string exclam = "!";
const std::string message2 = "Hello" + ", world" + exclam ;
std::cout << message2;
std::cout << std::endl;
return 0;
}

I'll take your word for it that this code appears in the book. But is it there
an example of code that's meant to compile, or is it presented as an example of
something that should not / does not compile?

Cheers,

- Alf

[C++ Newbie]

On 1 Apr, 10:19, "Alf P. Steinbach" <[e-mail]:

* C++ Newbie:

Consider the following program from "Accelerated C++", Koenig & Moo
[2004]:

Case [1]:
=====================================
#include <iostream>
#include <string>

int main()
{

// Ex 1-2
const std::string exclam = "!";
const std::string message2 = "Hello" + ", world" + exclam ;
std::cout << message2;
std::cout << std::endl;
return 0;
}

I'll take your word for it that this code appears in the book. But is it there
an example of code that's meant to compile, or is it presented as an example of
something that should not / does not compile?

Cheers,

- Alf

Hi Alf,

It is an exercise question in Chapter 1 (specifically Ex 1-2). The
reader is asked if the following definitions were valid.