file output question

[daduke40]

I have the piece of code:

outfile.open (filename.c_str());

where filename is the filename provided by the user.

However, how would I add .csv to end of that so I can change the file extension and create a new file?

so basically the outfile name would look like this

filename.txt.csv

-jeff

[sicarie]

You want to create an entirely new file (ie, copy the original into a new location and leave the first untouched)?

There are two ways to do this. The first is the ugly, QAD way to use 'system()' and the OS-dependent commands to do that (Linux would be 'cp /file/path/1 /file/path2', I'm not sure what it would be in DOS).

The second is the more elegant way to use the API of the OS you are on (I'm guessing this is Windows, you'd have to use the Win32 API).

Or did I completely mis-understand your question?

[daduke40]

You want to create an entirely new file (ie, copy the original into a new location and leave the first untouched)?

There are two ways to do this. The first is the ugly, QAD way to use 'system()' and the OS-dependent commands to do that (Linux would be 'cp /file/path/1 /file/path2', I'm not sure what it would be in DOS).

The second is the more elegant way to use the API of the OS you are on (I'm guessing this is Windows, you'd have to use the Win32 API).

Or did I completely mis-understand your question?

user inputs the file name : filename.txt so the program can open and grab data off it.

then I want the program to grab the filename.txt (or whatever they type in) and add .csv to the end of it so it creates a new file, just in a different format..

[sicarie]

Okay, so you just re-stated your question, but didn't answer mine. What happens to the original file? Does it still exist? Or are you actually changing the file?

The difference (in Unix) is :

cp /path/to/file1 /path/to/new/file

and

mv /path/to/file1 /new/path/to/thefile

In the first, you will be able to find file1 in both /path/to and /path/to/new. In the second /path/to/file1 no longer exists - it is now /new/path/to/thefile .

Do you see what I'm saying?

You also didn't post your OS.

[daduke40]

Okay, so you just re-stated your question, but didn't answer mine. What happens to the original file? Does it still exist? Or are you actually changing the file?

The difference (in Unix) is :

cp /path/to/file1 /path/to/new/file

and

mv /path/to/file1 /new/path/to/thefile

In the first, you will be able to find file1 in both /path/to and /path/to/new. In the second /path/to/file1 no longer exists - it is now /new/path/to/thefile .

Do you see what I'm saying?

You also didn't post your OS.

Im using windows, but I think we are making this too difficult than it is.

cout << "Name of file" ;

cin >> filename ;
infile.open(filename.c_str());
outfile.open (filename.c_str())
not basically i want to add the extension .csv to the outfile so it won't be copying over the original file, but it will output all new info into the new file created.

so basically..

Name of file: data.txt (data.txt inputted by the user)

then all new info will be put into a new file called data.txt.csv

make sense?

[Laharl]

You can just append ".csv" to the filename string, you know.

[daduke40]

You can just append ".csv" to the filename string, you know.

what do you mean...i just trying to make a new file with a .csv extension...i don't mean to make this complicated..

[sicarie]

what do you mean...i just trying to make a new file with a .csv extension...i don't mean to make this complicated..

Okay, so in your example, you open the original .txt file to copy, and then create the new .csv file to copy that into, so as Laharl said, it'd be something like

string s_appendCsv = ".csv";
filename = filename + s_appendCsv;
fout.open(filename,'w');
 

(assuming filename is a string) That doesn't look exactly right to me, and I can't say 100% why, but I'll update this if I figure it out...