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Pointer in C

Can somebody explain what the * mean after BYTE.. ( p = (BYTE*) &dataout [0];) this part make me confuse

Code:

Expand|Select|Wrap|Line Numbers
  1. void function ();
  2.  
  3. {
  4. BYTE *p
  5. WORD i
  6.  
  7.    ReadData ();
  8.  
  9.    p = (BYTE*) &dataout [0];
  10.  
  11.    for (i = 0; i <4096; i++)
  12.      {
  13.          *p++ = inputA
  14.      }
  15.  
  16. }
Thank you
Mar 7 '08 #1
1 1185
satch
23
Can somebody explain what the * mean after BYTE.. ( p = (BYTE*) &dataout [0];) this part make me confuse

Code:
Expand|Select|Wrap|Line Numbers
  1. void function ();
  2.  
  3. {
  4. BYTE *p
  5. WORD i
  6.  
  7.    ReadData ();
  8.  
  9.    p = (BYTE*) &dataout [0];
  10.  
  11.    for (i = 0; i <4096; i++)
  12.      {
  13.          *p++ = inputA
  14.      }
  15.  
  16. }
  17.  
Thank you
The * tells that you are typecasting a pointer.
Mar 7 '08 #2

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