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Question about NaN in C++

Hello everyone.
I am new to C++ and I am currently working through a book that is helping me out a lot.
I created an infinite for loop that will take numbers that users input and add them together. I have an int variable inside my for loop that adds to the total int outside the for loop.

I want the for loop to break if what they type is not a number. Currently, if you type in a NaN, it continously outputs text.

Something like:
if(NaN(total))
{
break;
}

Any help would be greatly appreciated.
Feb 21 '08 #1
2 1174
weaknessforcats
9,208 Expert Mod 8TB
What do you mean by "not-a-number" ??

Considering everything in the computer is a number, adn considering that if you use an int for data entry, you have to enter an int.

Exactly, what are you trying to do??
Feb 21 '08 #2
What do you mean by "not-a-number" ??

Considering everything in the computer is a number, adn considering that if you use an int for data entry, you have to enter an int.

Exactly, what are you trying to do??
Sorry for not clarifying, I want it to break the for loop when the user types in anything that isn't a number, like a character or string.
Feb 21 '08 #3

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