Help with C errors C2440 and C2664.

[johnsonbl]

pttempmonthaddr = &tempmonth;
pttempdayaddr = &tempday;

separate(date, pttempmonthaddr, pttempdayaddr);/*function call*/
printf("\nThe month entered is %s and day entered is %f.\n", pttempmonthaddr, *pttempdayaddr);
return 0;

error C2440: '=' : cannot convert from 'char (*__w64 )[81]' to 'char *'

error C2664: 'separate' : cannot convert parameter 3 from 'int *' to 'int'
There is no context in which this conversion is possible


I am getting the C2440 error in the top line and C2664 error in the 3rd line from top. Can somebody help me out as to why?

[weaknessforcats]

Probably your array definition has something top do with the C2440.

The C2664 is caused by a mismatch in the type of the third argument versus what you supplied. It looks like the third argument needs to be an int and you supplied an int*

I can't tell since you didn't post the definitions of your variables or your function prototype.

You mioght read this on arrays:

First, there are only one-dimensional arrays in C or C++. The number of elements in put between brackets:

int array[5];
 

That is an array of 5 elements each of which is an int.

int array[];
 

won't compile. You need to declare the number of elements.

Second, this array:

int array[5][10];
 

is still an array of 5 elements. Each element is an array of 10 int.

int array[5][10][15];
 

is still an array of 5 elements. Each element is an array of 10 elements where each element is an array of 15 int.

int array[][10];
 

won't compile. You need to declare the number of elements.

Third, the name of an array is the address of element 0

int array[5];
 

Here array is the address of array[0]. Since array[0] is an int, array is the address of an int. You can assign the name array to an int*.

int array[5][10];
 

Here array is the address of array[0]. Since array[0] is an array of 10 int, array is the address of an array of 10 int. You can assign the name array to a pointer to an array of 10 int:

int array[5][10];
 
int (*ptr)[10] = array;
 

Fourth, when the number of elements is not known at compile time, you create the array dynamically:

int* array = new int[value];
int (*ptr)[10] = new int[value][10];
int (*ptr)[10][15] = new int[value][10][15];
 

In each case value is the number of elements. Any other brackets only describe the elements.

Using an int** for an array of arrays is incorrect and produces wrong answers using pointer arithmetic. The compiler knows this so it won't compile this code:

int** ptr = new int[value][10];    //ERROR
 

new returns the address of an array of 10 int and that isn't the same as an int**.

Likewise:

int*** ptr = new int[value][10][15];    //ERROR
 

new returns the address of an array of 10 elements where each element is an array of 15 int and that isn't the same as an int***.

With the above in mind this array:

int array[10] = {0,1,2,3,4,5,6,7,8,9};
 

has a memory layout of

0 1 2 3 4 5 6 7 8 9

Wheras this array:

int array[5][2] = {0,1,2,3,4,5,6,7,8,9};
 

has a memory layout of

0 1 2 3 4 5 6 7 8 9

Kinda the same, right?

So if your disc file contains

0 1 2 3 4 5 6 7 8 9

Does it make a difference wheher you read into a one-dimensional array or a two-dimensional array? No.

Therefore, when you do your read use the address of array[0][0] and read as though you have a
one-dimensional array and the values will be in the correct locations.

[johnsonbl]

Probably your array definition has something top do with the C2440.

The C2664 is caused by a mismatch in the type of the third argument versus what you supplied. It looks like the third argument needs to be an int and you supplied an int*

I can't tell since you didn't post the definitions of your variables or your function prototype.

You mioght read this on arrays:

Thanks for the reply. I am still working on it. Here is the entire code.

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define MSIZE 81
void separate (char[], char[], int);/*function prototype*/
int main()
{
char date [MSIZE];
char tempmonth[MSIZE];
int tempday;
printf("\nEnter a month and a day. (Ex. June 14)\n");
gets_s(date);
printf("You entered: %s\n", date);

char *pttempmonthaddr;
int *pttempdayaddr;

pttempmonthaddr = &tempmonth;
pttempdayaddr = &tempday;

separate(date, pttempmonthaddr, pttempdayaddr);/*function call*/
printf("\nThe month entered is %s and day entered is %f.\n", *pttempmonthaddr, *pttempdayaddr);
return 0;
}
void separate(char *strin, char *strout, int *iout) /*function header*/
{
iout = 0;

while(*strin != '/0' && *strin != ' ')
*strout++ = *strin++;
*strout = '\0';
while (*strin != '\0' && *strin != ' ')
*strin++;

if(*strin != '\0')
*iout = atoi(strin);
}