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C++ array problem

2
I am so new at c++ and am totally stuck here.

How do I enter this into my compiler in order to find out what is stored in list after the code is executed?

int list[5];
list[0] = 5;
for (i = 1; i < 6; i++)
{
list[i] = i * i + 5;
if (i > 2)
list[i] = 2 * list[i] - list[i - 1];
}

Any help is appreciated.
Feb 1 '08 #1
3 1314
weaknessforcats
9,208 Expert Mod 8TB
As a beginner, write a second loop that displays each element of your array.

You can make a copy of the first loop and change the insides to a display of list[i].

Later, you should use your debugger to do this rather than putting stuff in the program that's for debug only.
Feb 1 '08 #2
Shel
2
As a beginner, write a second loop that displays each element of your array.

You can make a copy of the first loop and change the insides to a display of list[i].

Later, you should use your debugger to do this rather than putting stuff in the program that's for debug only.
Could you submit an example of how this is done?
Feb 1 '08 #3
it will be work correctly once,that's because you used list[2] before Initialized
Feb 2 '08 #4

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